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Assume that a0 and al holds the base address of str and strdst, respectively. int i = 0; While (str[i] != 0) { if (str[i] >= 'a' && str[i] <= 'z') strdst[i] = = 'z' (str[i] 'a'); - elseif (str[i] >= 'A' && str[i] <= 'Z') strdst[i] = = 'Z' (str[i] 'A'); else strdst[i] = str[i]; i++; }

Assume that a0 and al holds the base address of str and strdst, respectively. int i = 0; While (str[i] != 0) { if (str[i] >= 'a' && str[i] <= 'z') strdst[i] = = 'z' (str[i] 'a'); - elseif (str[i] >= 'A' && str[i] <= 'Z') strdst[i] = = 'Z' (str[i] 'A'); else strdst[i] = str[i]; i++; }

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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convert from high-level code into RISC-V assembly language

Assume that a0 and al holds the base address of str and strdst, respectively. int i = 0; %3D While (str[i] != 0) { if (str[i] >= 'a' && str[i] <= 'z') strdst[i] = 'z' (str[i] - 'a'); %3D elseif (str[i] >= 'A && str[i] <= 'Z') strdst[i] = 'Z' (str[i] - 'A'); else strdst[i] = str[i]; i++; }
Transcribed Image Text:Assume that a0 and al holds the base address of str and strdst, respectively. int i = 0; %3D While (str[i] != 0) { if (str[i] >= 'a' && str[i] <= 'z') strdst[i] = 'z' (str[i] - 'a'); %3D elseif (str[i] >= 'A && str[i] <= 'Z') strdst[i] = 'Z' (str[i] - 'A'); else strdst[i] = str[i]; i++; }
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