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Assume that a tornado is on the ground but has no forward speed. Using the principle of conservation of angular momentum, estimate the wind speeds of the tornado based on the measured rotation of the winds in the mesocyclone. Use the space to the right of each problem to work through the math. (1 mile-5280 ft) Conservation of angular momentum relates the rotational velocity, v, to the radial distance, r, from the center of rotation: (mesocyclone) V (mesocydone)=f(tornado)" V tomado) 1. radius of mesocyclone = 5 miles rotational velocity of mesocyclone = 5 mph radius of tornado = 1742 ft rotational velocity of tornado= 2. radius of mesocyclone = 4 miles rotational velocity of mesocyclone = 3 mph radius of tornado = 528 ft rotational velocity of tornado = _ 3. diameter of mesocyclone = 10 miles rotational velocity of mesocyclone = 6 mph radius of tornado = 528 ft rotational velocity of tornado =

Assume that a tornado is on the ground but has no forward speed. Using the principle of conservation of angular momentum, estimate the wind speeds of the tornado based on the measured rotation of the winds in the mesocyclone. Use the space to the right of each problem to work through the math. (1 mile-5280 ft) Conservation of angular momentum relates the rotational velocity, v, to the radial distance, r, from the center of rotation: (mesocyclone) V (mesocydone)=f(tornado)" V tomado) 1. radius of mesocyclone = 5 miles rotational velocity of mesocyclone = 5 mph radius of tornado = 1742 ft rotational velocity of tornado= 2. radius of mesocyclone = 4 miles rotational velocity of mesocyclone = 3 mph radius of tornado = 528 ft rotational velocity of tornado = _ 3. diameter of mesocyclone = 10 miles rotational velocity of mesocyclone = 6 mph radius of tornado = 528 ft rotational velocity of tornado =

Applications and Investigations in Earth Science (9th Edition)
Applications and Investigations in Earth Science (9th Edition)
9th Edition
ISBN:9780134746241
Author:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Publisher:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Chapter1: The Study Of Minerals
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Exercise 19.2 - Tornado Wind Speeds Assume that a tornado is on the ground but has no forward speed. Using the principle of conservation of angular momentum, estimate the wind speeds of the tornado based on the measured rotation of the winds in the mesocyclone. Use the space to the right of each problem to work through the math. (1 mile=5280 ft) Conservation of angular momentum relates the rotational velocity, v, to the radial distance, r, from the center of rotation: (mesocyclone) = tornadol (mesocydone) V (tornado) 1. radius of mesocyclone = 5 miles rotational velocity of mesocyclone = 5 mph radius of tornado = 1742 ft rotational velocity of tornado = 2. radius of mesocyclone = 4 miles rotational velocity of mesocyclone = 3 mph radius of tornado = 528 ft rotational velocity of tornado= 3. diameter of mesocyclone = 10 miles rotational velocity of mesocyclone = 6 mph radius of tornado = 528 ft rotational velocity of tornado =
Transcribed Image Text:Exercise 19.2 - Tornado Wind Speeds Assume that a tornado is on the ground but has no forward speed. Using the principle of conservation of angular momentum, estimate the wind speeds of the tornado based on the measured rotation of the winds in the mesocyclone. Use the space to the right of each problem to work through the math. (1 mile=5280 ft) Conservation of angular momentum relates the rotational velocity, v, to the radial distance, r, from the center of rotation: (mesocyclone) = tornadol (mesocydone) V (tornado) 1. radius of mesocyclone = 5 miles rotational velocity of mesocyclone = 5 mph radius of tornado = 1742 ft rotational velocity of tornado = 2. radius of mesocyclone = 4 miles rotational velocity of mesocyclone = 3 mph radius of tornado = 528 ft rotational velocity of tornado= 3. diameter of mesocyclone = 10 miles rotational velocity of mesocyclone = 6 mph radius of tornado = 528 ft rotational velocity of tornado =
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