Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a sample of size 130 with 73 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. 98% C.I. =

Q: Of 500 random people surveyed, 72 were smokers.  Find the 95% confidence interval. SE=0.0157

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Q: Find the indicated margin of error. Out of 260 trials, 150 turned out positive. Find the margin of…

A: It is given that the sample size (n) is 260 and the number of positive trials (x) is 150.

Q: Find the 95% confidence interval for each data set. What does this range mean?

A: As per guidelines we will only answer the first three subparts, please repost other subparts for…

Q: Find the indicated margin of error. Out of 330 trials, 150 turned out positive. Find the margin of…

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Q: Determine the sample size for the estimate of u if the margin of error E= 0.10, o=0.85, and the…

A: Given,Margin of error, E = 0.10Population standard deviation, σ = 0.85Confidence level, C = 99% =…

Q: Assume that a samlpe is used to estimate a population proportion p.  Find the margin of error E that…

A: Given that n=sample size=800p=probability of success=40%=0.40z= critical value for 98% confidence…

Q: If [330, 610] is a confidence interval for the population mean. Find the margin of eror. Select one:…

A: The upper limit of the confidence interval is (U) = 610 The lower limit of the confidence interval…

Q: Find ??/2 for the 93% confidence interval. Select one: A. 1.83 B. 1.81 C. 1.80 D. 1.82

A: Solution: Given information: Confidence level = 93% = 0.93 α=1-confidence level α=1-0.93= 0.07…

Q: Construct the confidence interval for the population mean . C=0.98, x=15.3, = 10.0, and n=75

A: The Confidence Interval formula is X  ±  Z s √(n) Where: X is the mean Z is the Z-value…

Q: Assume that population mean is to be estimated from the sample described. Use the sample results to…

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Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

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Q: A confidence interval was constructed to approximate a population proportion. the interval was from…

A: From the provided information, The confidence interval was from 30.5% to 41.5%.

Q: Suppose someone wanted an 75%-confidence interval. What value of z should they use? Choose the…

A: Level of significance ɑ=0.25

Q: Find the margin of error for each data from certain populations. 3. 45, 56, 61, 88, 91, 64, 38, 79,…

A: Given data: Confidence leval = 90% To find margin of error

Q: Construct a confidence interval of the population proportion at the given level of confidence. X =…

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Q: Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval…

A: Given data,n=258x=115Find the 95% confidence interval

Q: Construct a 99​% confidence interval of the population proportion using the given information.…

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Q: Assume that a sample is used to estimate a population proportion p. Find the margin of error E that…

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Q: Assume that a sample is used to estimate a population proportion p. To find the 95% confidence…

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Q: Find the sample size required to estimate the percentage of statistics students who take their…

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Q: Construct a 90​% confidence interval of the population proportion using the given information.…

A: x=240  n=300  p= 240/300 = 0.8 q = 1-p = 1-0.8 = 0.2

Q: Problem: Use the data given in Example #1 to construct a 95% confidence interval for the mean number…

A: Given data:

Q: Construct a 90% confidence interval of the population mean age for the college students in Example…

A: We have to find a...n , x̄, zc and E  b. Find the left and right endpoints of the confidence…

Q: Assume that population mean is to be estimated from the sample described. Use the sample results to…

A: Given information Sample size (n) = 49 Sample mean x̅ = 55.1 Standard deviation (s) = 4.8…

Q: In a survey of 6700 T.V. viewers, 3350 said they watch network news programs. Find the margin of…

A: n = 6700 x = 3350  p̂ = x/n = 3350/6700 = 0.50Confidence level (c) = 99% = 0.99Significance level…

Q: Find the sample size need to find the Population Proportion if the margin of error is 4%, the…

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Q: Tina catches a 14-pound bass.  She does not know the population mean or standard deviation.  So she…

A: From the provided information, The data values are as follow: 9, 12, 13, 10 and 10 Sample size (n) =…

Q: Find the confidence level and α for a. a 90% confidence interval. b. a 99% confidence interval.

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Q: 95%% Confidence, n=380, x =50 a O.0357 b) Oo 030l6 c)0.0408 d)0.0340

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Q: We would like to create a confidence interval for the mean. Which of the following would produce the…

A: Margin of error = Width/2

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A: Answer - Given, The sample size n = 1004,  and x = 575,  use a 90% confidence level

Q: Assume that a sample is being used to estimate a population mean . If n = 16, = 38, and s = 3, find…

A: Sample size n=16Sample mean=38Standard deviation=3

Q: t the confidence interval for the population mean. C=0.98, x=6.6, =0.8, and n=5

A: As the population standard deviation is known, we will use z distribution. At 98% confidence level,…

Q: Researchers studied the mean egg length (in millimeters) for a bird population. After taking a…

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Q: Find the confidence interval for a proportion.  Use the given data to construct a confidence…

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Q: C. FIND t a n = 15 for the 98% confidence interval for the mean.

A: Given problem is :