Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval for a sample of size 231 with 116 successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. < p <
Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval for a sample of size 231 with 116 successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. < p <
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![**Title: Calculating Confidence Interval for Population Proportion**
**Introduction:**
When you use a sample to estimate the population proportion \( p \) (for example, the proportion of people who prefer a certain brand), it's essential to determine how accurate this estimate is. This accuracy is often expressed as a confidence interval. Here, you'll learn how to find the 99% confidence interval for the population proportion using a given sample.
**Example Problem:**
Assume that a sample is used to estimate a population proportion \( p \). We need to find the 99% confidence interval for a sample of size 231 with 116 successes. Your answer should be in the form of a tri-linear inequality using decimals, not percentages, and should be accurate to three decimal places.
**Steps:**
1. **Determine the sample proportion, \(\hat{p}\):**
\[
\hat{p} = \frac{x}{n}
\]
Where \( x \) is the number of successes and \( n \) is the sample size.
\[
\hat{p} = \frac{116}{231}
\]
2. **Calculate the standard error (SE) for the proportion:**
\[
SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}}
\]
3. **Determine the Z-value for a 99% confidence level:**
The Z-value (critical value) for a 99% confidence interval is approximately 2.576. This value is derived from standard normal distribution tables.
4. **Calculate the margin of error (ME):**
\[
ME = Z \times SE
\]
5. **Determine the confidence interval:**
\[
CI = \hat{p} \pm ME
\]
6. **Express your confidence interval as a tri-linear inequality:**
\[
\text{Lower Bound} < p < \text{Upper Bound}
\]
**Interactive Exercise:**
Below are provided spaces to calculate and input your answer for the confidence interval:
\[
\underline{\hspace{2cm}} < p < \underline{\hspace{2cm}}
\]
By following these steps, you will determine the population proportion \( p \) with 99% confidence.
**Conclusion:**
Understanding confidence intervals is a vital concept in statistics that allows you to estimate](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff592c908-5fe4-46f5-b3d4-3020e7f71c73%2F57ad8244-6de1-44c9-9405-46c0e1ea4d35%2Fyssyhi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Calculating Confidence Interval for Population Proportion**
**Introduction:**
When you use a sample to estimate the population proportion \( p \) (for example, the proportion of people who prefer a certain brand), it's essential to determine how accurate this estimate is. This accuracy is often expressed as a confidence interval. Here, you'll learn how to find the 99% confidence interval for the population proportion using a given sample.
**Example Problem:**
Assume that a sample is used to estimate a population proportion \( p \). We need to find the 99% confidence interval for a sample of size 231 with 116 successes. Your answer should be in the form of a tri-linear inequality using decimals, not percentages, and should be accurate to three decimal places.
**Steps:**
1. **Determine the sample proportion, \(\hat{p}\):**
\[
\hat{p} = \frac{x}{n}
\]
Where \( x \) is the number of successes and \( n \) is the sample size.
\[
\hat{p} = \frac{116}{231}
\]
2. **Calculate the standard error (SE) for the proportion:**
\[
SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}}
\]
3. **Determine the Z-value for a 99% confidence level:**
The Z-value (critical value) for a 99% confidence interval is approximately 2.576. This value is derived from standard normal distribution tables.
4. **Calculate the margin of error (ME):**
\[
ME = Z \times SE
\]
5. **Determine the confidence interval:**
\[
CI = \hat{p} \pm ME
\]
6. **Express your confidence interval as a tri-linear inequality:**
\[
\text{Lower Bound} < p < \text{Upper Bound}
\]
**Interactive Exercise:**
Below are provided spaces to calculate and input your answer for the confidence interval:
\[
\underline{\hspace{2cm}} < p < \underline{\hspace{2cm}}
\]
By following these steps, you will determine the population proportion \( p \) with 99% confidence.
**Conclusion:**
Understanding confidence intervals is a vital concept in statistics that allows you to estimate
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