Assume that a sample is used to estimate a population mean u. Find the margin of error M.E. that corresponds to a sample of size 22 with a mean of 30.6 and a standard deviation of 7.9 at a confidence level of 99%. Report ME accurate to one decimal place because the sample statistics are presented with this accuracy. M.E. = Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.

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**Estimating the Margin of Error for a Population Mean**

To estimate the population mean \(\mu\), begin with a sample. Let's find the margin of error \(M.E.\) for a sample of size 22, with a mean of 30.6 and a standard deviation of 7.9, at a 99% confidence level.

### Steps to Calculate the Margin of Error

1. **Determine the Sample Statistics:**
   - Sample size (n) = 22
   - Sample mean (\(\overline{x}\)) = 30.6
   - Sample standard deviation (s) = 7.9

2. **Identify the Confidence Level:**
   - Confidence level = 99%

3. **Find the Critical Value:**
   - For a 99% confidence level, find the corresponding t-value from the t-distribution table. Use degrees of freedom (df) = \( n - 1 = 22 - 1 = 21 \).

4. **Calculate the Margin of Error (M.E.):**
   - Formula: \( M.E. = t \times \frac{s}{\sqrt{n}} \)
   - Ensure that the margin of error is reported to one decimal place due to the accuracy of the sample statistics.
   - Conduct calculations without preliminary rounding, but the critical value may be rounded to three decimal places if necessary.

### Please Enter the Calculated Margin of Error

\[ M.E. = \boxed{} \]

### Important Note:

The answer should reflect accurate representation considering the specific context provided. The critical value and standard deviation must consider formatting and precision as specified.
Transcribed Image Text:**Estimating the Margin of Error for a Population Mean** To estimate the population mean \(\mu\), begin with a sample. Let's find the margin of error \(M.E.\) for a sample of size 22, with a mean of 30.6 and a standard deviation of 7.9, at a 99% confidence level. ### Steps to Calculate the Margin of Error 1. **Determine the Sample Statistics:** - Sample size (n) = 22 - Sample mean (\(\overline{x}\)) = 30.6 - Sample standard deviation (s) = 7.9 2. **Identify the Confidence Level:** - Confidence level = 99% 3. **Find the Critical Value:** - For a 99% confidence level, find the corresponding t-value from the t-distribution table. Use degrees of freedom (df) = \( n - 1 = 22 - 1 = 21 \). 4. **Calculate the Margin of Error (M.E.):** - Formula: \( M.E. = t \times \frac{s}{\sqrt{n}} \) - Ensure that the margin of error is reported to one decimal place due to the accuracy of the sample statistics. - Conduct calculations without preliminary rounding, but the critical value may be rounded to three decimal places if necessary. ### Please Enter the Calculated Margin of Error \[ M.E. = \boxed{} \] ### Important Note: The answer should reflect accurate representation considering the specific context provided. The critical value and standard deviation must consider formatting and precision as specified.
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