Assume that a sample is used to estimate a population mean u. Find the 99% confidence interval for a sample of size 68 with a mean of 36.2 and a standard deviation of 18.9. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places.

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Help please.
Assume that a sample is used to estimate a
population mean u. Find the 99% confidence
interval for a sample of size 68 with a mean of
36.2 and a standard deviation of 18.9. Enter your
answer as an open-interval (i.e., parentheses)
accurate to 3 decimal places.
99% C.I. =
The answer should be obtained without any
preliminary rounding.
Transcribed Image Text:Assume that a sample is used to estimate a population mean u. Find the 99% confidence interval for a sample of size 68 with a mean of 36.2 and a standard deviation of 18.9. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. 99% C.I. = The answer should be obtained without any preliminary rounding.
Expert Solution
Step 1

Obtain the 99% confidence interval to estimate the population mean.

 

The 99% confidence interval to estimate the population mean is obtained below:

 

The formula for the Confidence interval for mean is:

Statistics homework question answer, step 1, image 1

Obtain the degrees of freedom.

The degrees of freedom is obtained below:

Statistics homework question answer, step 1, image 2

 

Use EXCEL Procedure for finding the critical value of t.

 

Follow the instruction to obtain the critical value of t:

 

  1. Open EXCEL
  2. Go to Formula bar.
  3. In formula bar enter the function as“=TINV”
  4. Enter the probability as 0.01.
  5. Enter the degrees of freedom as 67.
  6. Click enter

 

EXCEL output:

 

From the EXCEL output, the critical value of t at 0.01 level of significance with the 67 degrees of freedom is 2.6512.

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