Assume that a researcher randomly selects 14 newborn babies and counts the number of girls selected, x. The probabilities corresponding to the 14 possible values of x are summarized in the given table. Answer the question using the table. Probabilities of Girls x(girls)| P(x) |x(girls)| P(x) |x(girls)| P(x) 0.000 5 0.122 10 0.061 1 0.001 0.183 11 0.022 0.006 7 0.209 12 0.006 3 0.022 0.183 13 0.001 4 0.061 0.122 14 0.000 25) Find the probability of selecting 12 or more girls. A) 0.006 25) B) 0.007 C) 0.022 D) 0.001

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Assume that a researcher randomly selects 14 newborn babies and counts the number of girls selected, x. The probabilities corresponding to the 14 possible values of x are summarized in the given table.

Answer the question using the table.

 

Find the probability of selecting 12 or more girls.

A) 0.006

B) 0.007

C) 0.022

D) 0.001

### Probability of Selecting Girls from a Group of 14 Newborn Babies

Assume that a researcher randomly selects 14 newborn babies and counts the number of girls selected, \( x \). The probabilities corresponding to the 14 possible values of \( x \) are summarized in the given table. Answer the question using the table.

#### Probabilities of Girls

| x (girls) | P(x) | x (girls) | P(x) | x (girls) | P(x) |
| --- | --- | --- | --- | --- | --- |
| 0 | 0.000 | 5 | 0.122 | 10 | 0.061 |
| 1 | 0.001 | 6 | 0.183 | 11 | 0.022 |
| 2 | 0.006 | 7 | 0.209 | 12 | 0.006 |
| 3 | 0.022 | 8 | 0.183 | 13 | 0.001 |
| 4 | 0.061 | 9 | 0.122 | 14 | 0.000 |

#### Question:
**25) Find the probability of selecting 12 or more girls.**

Options:
A) 0.006  
B) 0.007  
C) 0.022  
D) 0.001  

To find the probability of selecting 12 or more girls, we sum the probabilities for \( x = 12 \), \( x = 13 \), and \( x = 14 \).

\[ P(x \geq 12) = P(12) + P(13) + P(14) \]
\[ P(x \geq 12) = 0.006 + 0.001 + 0.000 \]

So, \( P(x \geq 12) = 0.007 \).

**Answer: B) 0.007**
Transcribed Image Text:### Probability of Selecting Girls from a Group of 14 Newborn Babies Assume that a researcher randomly selects 14 newborn babies and counts the number of girls selected, \( x \). The probabilities corresponding to the 14 possible values of \( x \) are summarized in the given table. Answer the question using the table. #### Probabilities of Girls | x (girls) | P(x) | x (girls) | P(x) | x (girls) | P(x) | | --- | --- | --- | --- | --- | --- | | 0 | 0.000 | 5 | 0.122 | 10 | 0.061 | | 1 | 0.001 | 6 | 0.183 | 11 | 0.022 | | 2 | 0.006 | 7 | 0.209 | 12 | 0.006 | | 3 | 0.022 | 8 | 0.183 | 13 | 0.001 | | 4 | 0.061 | 9 | 0.122 | 14 | 0.000 | #### Question: **25) Find the probability of selecting 12 or more girls.** Options: A) 0.006 B) 0.007 C) 0.022 D) 0.001 To find the probability of selecting 12 or more girls, we sum the probabilities for \( x = 12 \), \( x = 13 \), and \( x = 14 \). \[ P(x \geq 12) = P(12) + P(13) + P(14) \] \[ P(x \geq 12) = 0.006 + 0.001 + 0.000 \] So, \( P(x \geq 12) = 0.007 \). **Answer: B) 0.007**
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