Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1: Draw a graph and find P6. the 6th percentile. This is the bone density score separating the bottom 6% from the top 94%. Which graph represents P? Choose the correct graph below. OA. P6 Q OB. The bone density score corresponding to Pg is. (Round to two decimal places as needed.) Pe Q ๔ ปี CIE O C. P6 O D. A

Q: Assume that a randomly selected subject is given a bone density test. Bone density test scores are…

A: Given that  Mean = 0 , Standard deviation = 1

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A: given data, normal distribution , μ=100σ=15we have to find out the shaded region for the given…

Q: Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those…

A: Here the given graph is

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A:

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Q: The area of the shaded region is

A: Consider X denotes the IQ score. X~Nμ=100,σ=15

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A: Mean(µ) = 100Standard deviations (σ) = 15X ~ N (µ, σ )= N(100, 15)

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Q: Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those…

A: given data  normal distribution  μ= 100σ= 15 p(70<x<125) = ?

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A: normal distribution μ = 100σ = 15 P(85<x<110) = ?

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A: See the Excel output

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Q: Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those…

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Q: Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those…

A: Solution:- From given information Mean = 100 Standard deviation =15

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