Assume that a procedure yields a binomial distribution with n=1231n=1231 trials and the probability of success for one trial is p=0.77p=0.77.Find the mean for this binomial distribution.(Round answer to one decimal place.) μ =   Find the standard deviation for this distribution.(Round answer to two decimal places.) σ =   Use the range rule of thumb to find the minimum usual value μ–2σ and the maximum usual value μ+2σ.Enter the answer as an interval using square-brackets only with whole numbers. usual values =

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Assume that a procedure yields a binomial distribution with n=1231n=1231 trials and the probability of success for one trial is p=0.77p=0.77.

Find the mean for this binomial distribution.
(Round answer to one decimal place.)

μ =

 

Find the standard deviation for this distribution.
(Round answer to two decimal places.)

σ =

 

Use the range rule of thumb to find the minimum usual value μ–2σ and the maximum usual value μ+2σ.
Enter the answer as an interval using square-brackets only with whole numbers.

usual values = 

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