Assume that a procedure yields a binomial distribution with n=1348 trials and the probability of succe for one trial is p 52%. Find the mean for this binomial distribution. (Round answer to one decimal place.) f Find the standard deviation for this distribution. (Round answer to two decimal places.) Use the range rule of thumb to find the minimum usual value u-20 and the maximum usual value µ+20. Enter answer as an interval using square-brackets only with whole numbers.

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**Understanding Binomial Distribution**

---

### Problem Statement:

Assume that a procedure yields a binomial distribution with \( n = 1348 \) trials and the probability of success for one trial is \( p = 52\% \).

1. **Find the mean for this binomial distribution.**
   *(Round answer to one decimal place.)*

   \[
   \mu = \_\_\_
   \]

2. **Find the standard deviation for this distribution.**
   *(Round answer to two decimal places.)*

   \[
   \sigma = \_\_\_
   \]

3. **Use the range rule of thumb to find the minimum usual value \(\mu - 2\sigma\) and the maximum usual value \(\mu + 2\sigma\).**  
   Enter answer as an interval using square-brackets only with whole numbers.

   \[
   \text{usual values} = \_\_\_
   \]

### Solution Outline:

- **Calculation of Mean (\(\mu\)):**

   For a binomial distribution, the mean (\(\mu\)) is given by:  
   \[
   \mu = n \cdot p
   \]
   where:
   \[
   n = 1348 \quad \text{and} \quad p = 0.52
   \]

- **Calculation of Standard Deviation (\(\sigma\)):**

   For a binomial distribution, the standard deviation (\(\sigma\)) is given by:  
   \[
   \sigma = \sqrt{n \cdot p \cdot (1 - p)}
   \]

- **Use of Range Rule of Thumb:**

   To find the usual range, calculate:
   \[
   \mu - 2\sigma \quad \text{and} \quad \mu + 2\sigma
   \]

### Step-by-Step Solution:

1. **Mean Calculation:**

   \[
   \mu = n \cdot p = 1348 \cdot 0.52
   \]

   \(\mu = \_\_\_ \) (rounding to one decimal place)

2. **Standard Deviation Calculation:**

   \[
   \sigma = \sqrt{1348 \cdot 0.52 \cdot 0.48}
   \]

   \(\sigma = \_\_\_\) (rounding to two
Transcribed Image Text:**Understanding Binomial Distribution** --- ### Problem Statement: Assume that a procedure yields a binomial distribution with \( n = 1348 \) trials and the probability of success for one trial is \( p = 52\% \). 1. **Find the mean for this binomial distribution.** *(Round answer to one decimal place.)* \[ \mu = \_\_\_ \] 2. **Find the standard deviation for this distribution.** *(Round answer to two decimal places.)* \[ \sigma = \_\_\_ \] 3. **Use the range rule of thumb to find the minimum usual value \(\mu - 2\sigma\) and the maximum usual value \(\mu + 2\sigma\).** Enter answer as an interval using square-brackets only with whole numbers. \[ \text{usual values} = \_\_\_ \] ### Solution Outline: - **Calculation of Mean (\(\mu\)):** For a binomial distribution, the mean (\(\mu\)) is given by: \[ \mu = n \cdot p \] where: \[ n = 1348 \quad \text{and} \quad p = 0.52 \] - **Calculation of Standard Deviation (\(\sigma\)):** For a binomial distribution, the standard deviation (\(\sigma\)) is given by: \[ \sigma = \sqrt{n \cdot p \cdot (1 - p)} \] - **Use of Range Rule of Thumb:** To find the usual range, calculate: \[ \mu - 2\sigma \quad \text{and} \quad \mu + 2\sigma \] ### Step-by-Step Solution: 1. **Mean Calculation:** \[ \mu = n \cdot p = 1348 \cdot 0.52 \] \(\mu = \_\_\_ \) (rounding to one decimal place) 2. **Standard Deviation Calculation:** \[ \sigma = \sqrt{1348 \cdot 0.52 \cdot 0.48} \] \(\sigma = \_\_\_\) (rounding to two
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