Assume that a procedure yields a binomial distribution with n = 983 trials and the probability of successfor one trial is p = 0.15.Find the mean for this binomial distribution.(Round answer to one decimal place.)H = | 147.5Find the standard deviation for this distribution.(Round answer to two decimal places.)o = 11.20Use the range rule of thumb to find the minimum usual value u-20 and the maximum usual value u+20.Enter answer as an interval using square-brackets only with whole numbers.usual values =[125.1,169.9]

List of formulas : For Binomial distribution , Mean =μ = np Standard deviation = σ =np(1-p)…

Answered: Assume that a procedure yields a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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llustration 17.8. For a binomial distribution the mean is 6 and standard deviation is 2. Write out all the terms of the distri- bution.
Assume that a procedure yields a binomial distribution with 7 = 1452 trials and the probability of success for one trial is p = 0.33. Find the mean for this binomial distribution. (Round answer to one decimal place.) P= Find the standard deviation for this distribution. (Round answer to two decimal places.) σ= Use the range rule of thumb to find the minimum usual value μ-20 and the maximum usual value μ+20. Enter answer as an interval using square-brackets only with whole numbers. usual values = > Next Question 84°F 15 HOLD Mostly cloudy 9-
Assume that a procedure yields a binomial distribution with n = 615 trials and the probability of success for one trial is p 27%. Find the mean for this binomial distribution. (Round answer to one decimal place.) μl = Find the standard deviation for this distribution. (Round answer to two decimal places.) σ= Use the range rule of thumb to find the minimum usual value µ-20 and the maximum usual value μ+20. Enter answer as an interval using square-brackets only with whole numbers. usual values =
Assume the data set described is normally distributed with the given mean and standard deviation, and with n total values. Find the approximate number of data values that will fall in the given range. Mean-8 Standard deviation-1.5 n-45 Range: 6.5 to 9.5 In this case, we expect about 52 data values to fall between 6.5 and 9.5.
Assume that a procedure yields a binomial distribution with n = 1167 trials and the probability of success for one trial is p = 73%. Find the mean for this binomial distribution. (Round answer to one decimal place.) P= Find the standard deviation for this distribution. (Round answer to two decimal places.). Use the range rule of thumb to find the minimum usual value µ-20 and the maximum usual value µ+20. Enter answer as an interval using square-brackets only with whole numbers. usual values= Question Help: Written Example Message instructor Submit Question 44°F Clear Jump to Answer W S # 3 E D 4 Q Search R C 5 LL T G Y H B J
Assume that a procedure yields a binomial distribution with n = 815 trials and the probability of success for one trial is p = 0.32. Find the mean for this binomial distribution. (Round answer to one decimal place.) fl Find the standard deviation for this distribution. (Round answer to two decimal places.) σ = Use the range rule of thumb to find the minimum usual value μ-20 and the maximum usual value μ+20. Enter answer as an interval using square-brackets only with whole numbers. usual values=
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Assume that a procedure yields a binomial distribution with n = 48 trials and the probability of success for one trial is p = 0.37. Find the mean for this binomial distribution. Round your answer to at least one decimal. μ = Find the standard deviation for this distribution. Round your answer to at least two decimals. σ =
Assume that a procedure yields a binomial distribution with n = 513 trials and the probability of success for one trial is p = 0.27. Find the mean for this binomial distribution. (Round answer to one decimal place.) Find the standard deviation for this distribution. (Round answer to two decimal places.) O = Use the range rule of thumb to find the minimum usual value u-20 and the maximum usual value u+20. Enter answer as an interval using square-brackets only with whole numbers. usual values =
Assume that a procedure yields a binomial distribution with n=499 trials and the probability of success for one trial is p=0.84Find the mean for this binomial distribution.(Round answer to one decimal place.)μ= Find the standard deviation for this distribution.(Round answer to two decimal places.)σ=Use the range rule of thumb to find the minimum usual value μ-2σ and the maximum usual value μ+2σ.Enter answer as an interval using square-brackets only with whole numbers.usual values =
A car battery's lifetime has an unknown distribution that is symmetric around its average of 800 days. The standard deviation of the lifetime is 50 days. Use Chebyshev's theorem to find an upper bound for the percentage of batteries that last shorter than 550 days? A. 5.56% B. 2.00% O C. 1.39% O D. 3.13%
Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find Upper P 10 ,the 10 th percentile. This is the bone density score separating the bottom 10% from the top 90%. a. The bone density score corresponding to Upper P 10 is (Round to two decimal places as needed.)

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