Assume that a procedure yields a binomial distribution with n = 763 trials and the probability of success for one trial is p = 4/15. Find the mean for this binomial distribution. (Round answer to one decimal place.) f= Find the standard deviation for this distribution. (Round answer to two decimal places.) σ=
Assume that a procedure yields a binomial distribution with n = 763 trials and the probability of success for one trial is p = 4/15. Find the mean for this binomial distribution. (Round answer to one decimal place.) f= Find the standard deviation for this distribution. (Round answer to two decimal places.) σ=
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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question 10

Transcribed Image Text:The problem presents a binomial distribution scenario:
- Number of trials (\(n\)): 763
- Probability of success for one trial (\(p\)): 4/15
Tasks:
1. **Calculate the Mean (\(\mu\))**:
- Formula: \(\mu = n \times p\)
- Round your answer to one decimal place.
- Input the value in the provided box labeled \(\mu =\).
2. **Calculate the Standard Deviation (\(\sigma\))**:
- Formula: \(\sigma = \sqrt{n \times p \times (1-p)}\)
- Round your answer to two decimal places.
- Input the value in the provided box labeled \(\sigma =\).
3. **Determine the Usual Values**:
- Use the range rule of thumb: Minimum usual value = \(\mu - 2\sigma\) and Maximum usual value = \(\mu + 2\sigma\).
- Enter the interval in square brackets and ensure it contains only whole numbers in the box labeled "usual values =".
Press the "Next Question" button to proceed after finishing these calculations.
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