Assume that a procedure yields a binomial distribution with a trial repeater Use the binomial probability formula to find the probability of x successes probability p of success on a single trial. Round to three decimal places. n = 10, x = 2, p = !!

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**Understanding Binomial Distribution**

In this section, we will explore how to use the binomial probability formula to determine the probability of achieving a specific number of successes in a fixed number of trials. 

**Description:**

Given a procedure that yields a binomial distribution, we will focus on a scenario where the trial is repeated \( n \) times. The goal is to determine the probability of obtaining \( x \) successes, given that the probability \( p \) of success on a single trial is known. 

To calculate this, we will use the binomial probability formula and round the final answer to three decimal places for precision.

**Formula:**

The binomial probability formula is:

\[ P(X = x) = \binom{n}{x} p^x (1-p)^{n-x} \]

Where:
- \( P(X = x) \): The probability of getting exactly \( x \) successes.
- \(\binom{n}{x}\): The number of combinations of \( n \) items taken \( x \) at a time.
- \( p \): The probability of success on a single trial.
- \( n \): The total number of trials.
- \( x \): The number of successes.

**Example Problem:**

In this example, the values are given as follows:
- \( n = 10 \): Number of trials
- \( x = 2 \): Number of successes
- \( p = \frac{1}{3} \): Probability of success

By substituting these values into the binomial probability formula, students are required to find the probability of exactly 2 successes out of 10 trials. The final answer should be rounded to three decimal places.

**Detailed Steps:**

1. **Calculate the binomial coefficient** \( \binom{10}{2} \):
\[ \binom{10}{2} = \frac{10!}{2!(10-2)!} = \frac{10 \times 9}{2 \times 1} = 45 \]

2. **Calculate the term** \( p^x \):
\[ \left( \frac{1}{3} \right)^2 = \frac{1}{9} \]

3. **Calculate the term** \( (1 - p)^{n-x} \):
\[ \left( 1 - \frac{1}{3} \right)^{10-2}
Transcribed Image Text:**Understanding Binomial Distribution** In this section, we will explore how to use the binomial probability formula to determine the probability of achieving a specific number of successes in a fixed number of trials. **Description:** Given a procedure that yields a binomial distribution, we will focus on a scenario where the trial is repeated \( n \) times. The goal is to determine the probability of obtaining \( x \) successes, given that the probability \( p \) of success on a single trial is known. To calculate this, we will use the binomial probability formula and round the final answer to three decimal places for precision. **Formula:** The binomial probability formula is: \[ P(X = x) = \binom{n}{x} p^x (1-p)^{n-x} \] Where: - \( P(X = x) \): The probability of getting exactly \( x \) successes. - \(\binom{n}{x}\): The number of combinations of \( n \) items taken \( x \) at a time. - \( p \): The probability of success on a single trial. - \( n \): The total number of trials. - \( x \): The number of successes. **Example Problem:** In this example, the values are given as follows: - \( n = 10 \): Number of trials - \( x = 2 \): Number of successes - \( p = \frac{1}{3} \): Probability of success By substituting these values into the binomial probability formula, students are required to find the probability of exactly 2 successes out of 10 trials. The final answer should be rounded to three decimal places. **Detailed Steps:** 1. **Calculate the binomial coefficient** \( \binom{10}{2} \): \[ \binom{10}{2} = \frac{10!}{2!(10-2)!} = \frac{10 \times 9}{2 \times 1} = 45 \] 2. **Calculate the term** \( p^x \): \[ \left( \frac{1}{3} \right)^2 = \frac{1}{9} \] 3. **Calculate the term** \( (1 - p)^{n-x} \): \[ \left( 1 - \frac{1}{3} \right)^{10-2}
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