Assume that a procedure yields a binomial distribution with a trial repeated n=11n=11 times. Find the probability of exactly x=6x=6 successes given the probability p=43%p=43% of success on a single trial. (Report answer accurate to 4 decimal places.) P(X)=
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Assume that a procedure yields a binomial distribution with a trial repeated n=11n=11 times. Find the
(Report answer accurate to 4 decimal places.)
P(X)=
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- n=2485; p=0.63 find the standard deviation, o, for the binomial distribution which has the stated values of n and p.Assume that a procedure yields a binomial distribution with 7 = 1452 trials and the probability of success for one trial is p = 0.33. Find the mean for this binomial distribution. (Round answer to one decimal place.) P= Find the standard deviation for this distribution. (Round answer to two decimal places.) σ= Use the range rule of thumb to find the minimum usual value μ-20 and the maximum usual value μ+20. Enter answer as an interval using square-brackets only with whole numbers. usual values = > Next Question 84°F 15 HOLD Mostly cloudy 9-Assume that a procedure yields a binomial distribution with n = 615 trials and the probability of success for one trial is p 27%. Find the mean for this binomial distribution. (Round answer to one decimal place.) μl = Find the standard deviation for this distribution. (Round answer to two decimal places.) σ= Use the range rule of thumb to find the minimum usual value µ-20 and the maximum usual value μ+20. Enter answer as an interval using square-brackets only with whole numbers. usual values =
- Assume that a procedure yields a binomial distribution with n=1222n=1222 trials and the probability of success for one trial is p=38%p=38%.Find the mean for this binomial distribution.(Round answer to one decimal place.)μ=μ= Find the standard deviation for this distribution.(Round answer to two decimal places.)σ=σ= Use the range rule of thumb to find the minimum usual value μ–2σ and the maximum usual value μ+2σ.Enter answer as an interval using square-brackets only with whole numbers.usual values =Assume that a procedure yields a binomial distribution with n = 1167 trials and the probability of success for one trial is p = 73%. Find the mean for this binomial distribution. (Round answer to one decimal place.) P= Find the standard deviation for this distribution. (Round answer to two decimal places.). Use the range rule of thumb to find the minimum usual value µ-20 and the maximum usual value µ+20. Enter answer as an interval using square-brackets only with whole numbers. usual values= Question Help: Written Example Message instructor Submit Question 44°F Clear Jump to Answer W S # 3 E D 4 Q Search R C 5 LL T G Y H B JThe mean is µ = 15.2 and the standard deviation is Η = 0.9.Find the probability that X is between 14.3 and 16.1.
- Assume that a procedure yields a binomial distribution with n = 815 trials and the probability of success for one trial is p = 0.32. Find the mean for this binomial distribution. (Round answer to one decimal place.) fl Find the standard deviation for this distribution. (Round answer to two decimal places.) σ = Use the range rule of thumb to find the minimum usual value μ-20 and the maximum usual value μ+20. Enter answer as an interval using square-brackets only with whole numbers. usual values=You are conducting a study to see if the probability of a true negative on a test for a certain cancer is significantly different from 63%. With H, :p 63% you obtain a test statistic of z = - 1.222. Find the p-value accurate to 4 decimal places. p-value =Assume that a procedure yields a binomial distribution with n = 1407 trials and the probability of success for one trial is p = 0.59. Find the mean for this binomial distribution. (Round answer to one decimal place.) μl = Find the standard deviation for this distribution. (Round answer to two decimal places.) J = Use the range rule of thumb to find the minimum usual value µ-20 and the maximum usual value μ+20. Enter answer as an interval using square-brackets only with whole numbers. usual values= Question Help: Message instructor Submit Question Jump to Answer
- Assume that a procedure yields a binomial distribution with n=1231n=1231 trials and the probability of success for one trial is p=0.77p=0.77.Find the mean for this binomial distribution.(Round answer to one decimal place.) μ = Find the standard deviation for this distribution.(Round answer to two decimal places.) σ = Use the range rule of thumb to find the minimum usual value μ–2σ and the maximum usual value μ+2σ.Enter the answer as an interval using square-brackets only with whole numbers. usual values =Suppose that the weight of an newborn fawn is Uniformly distributed between 2.2 and 3.8 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. The mean of this distribution is The standard deviation is The probability that fawn will weigh exactly 2.4 kg is P(x = 2.4) = The probability that a newborn fawn will be weigh between 2.9 and 3.7 is P(2.9 < x < 3.7) = The probability that a newborn fawn will be weigh more than 2.72 is P(x > 2.72) = P(x > 2.8 | x < 3.5) = Find the 25th percentile.