Assume that a pin-ended column of length L has a square cross section of dimensions di di and has a critical buckling load of P1. What is the relative increase in load-carrying capacity if the cross-sectional dimensions of the column are doubled? 2d₁ 2d₁

Compute for the maximum allowable distributed load o that can be applied to the simply supported beam as shown in Figure M-Va. The beam's cross section is detailed in Figure M-Vb. @(N/m) Allowable Stresses: Fiber Stress = +13.5 MPa / -12 MPa Transverse Shear Stress at NA = 900 kPa Transverse Shear Stress at Junction 800 2 m Figure M-Va 2 m Draw the flexural and shear stress distributions of the cross section. T 40 40 40 Figure M-Vb 40 120 mm

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The failure stress of a homogeneous steel bar having a diameter of 10 mm is 250 MPa. Using a factor of safety of 2.0, calculate the maximum load in N that the bar can support. A 12500*pi B 6250*pi 3125*pi 1563*pi

A cantilever of length L has a solid circular cross section of diameter D and carries a vertically downward load Wat its free end. The modulus of rigidity of the cantilever is G. Calculate the shear stress distribution across a section of the cantilever and hence determine the deflection due to shear at its free end. Ans. t = 16 W(1–4y²ID²)/3¤D², 40WL/9#GD² (downwards).

plz, solve this question ,it is not graded question.   Reg.no : 5395

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Given figure shows a portal frame with loads. All members of frame have same plastic moment of resistance Mp. The collapse load W is 2W W L/2 Constant Mp L/2 KL/2- +LI2 L/2

Higdon

(b) Figure Q4(a) shows a steel beam with length of 4 m that is supported by a steel column at point B. The steel column of AB has a rectangular cross section (40 mm× 70 mm). The ends are assumed to be pin connected. The yield stress of steel is o y = 250 MPa. The Modulus Elasticity of the steel is 200 GPa. Use factor of safety of 1.5. (i) Check whether the Euler's equation is appropriate or not. (ii) Determine the maximum distributed load (W) that can be applied to the beam so that the column of AB does not buckle.