Assume all the conditions of this test have been met. Using the p-value from the output, what can we conclude at a = 0.01? Analysis of Variance for Time Source df MS P Brand 3 365.28 121.76 16.57 0.000 Error 36 264.50 7.35 Total 39 629.78 Fail to reject the null hypothesis and conclude that at least one mean differs from the other means. Reject the null hypothesis and conclude that at least one mean differs from the other means. O Reject the null hypothesis and conclude that there is insufficient evidence to say that the means are not all equal. O Fail to reject the null hypothesis and conclude that there is insufficient evidence to say that the means are not all equal.

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A consumer group plans a comparative study of the mean life of four different brands of batteries. Ten batteries of each brand will be randomly selected and the time until the energy level falls below a pre-specified level is measured.

Assume all the conditions of this test have been met. Using the p-value from the output, what can we conclude at α = 0.01?

**Analysis of Variance for Time:**

| Source | df | SS     | MS    | F     | P   |
|--------|----|--------|-------|-------|-----|
| Brand  | 3  | 365.28 | 121.76| 16.57 | 0.000 |
| Error  | 36 | 264.50 | 7.35  |       |     |
| Total  | 39 | 629.78 |       |       |     |

**Options for Conclusion:**

1. Fail to reject the null hypothesis and conclude that at least one mean differs from the other means.
2. Reject the null hypothesis and conclude that at least one mean differs from the other means.
3. Reject the null hypothesis and conclude that there is insufficient evidence to say that the means are not all equal.
4. Fail to reject the null hypothesis and conclude that there is insufficient evidence to say that the means are not all equal.

**Explanation:**

In this analysis of variance (ANOVA), we are given the following values:

- **Degrees of freedom (df):** Represents the number of values that are free to vary.
- **Sum of squares (SS):** Measures the total variability in the data.
- **Mean square (MS):** An average of the squared deviations (SS divided by df).
- **F-value:** A ratio of the variance explained by the model to the variance within the groups.
- **P-value:** Indicates the probability of observing the F-value if the null hypothesis is true.

Given the p-value of 0.000, which is less than α = 0.01, we can reject the null hypothesis and conclude that at least one brand mean differs from the others.
Transcribed Image Text:Assume all the conditions of this test have been met. Using the p-value from the output, what can we conclude at α = 0.01? **Analysis of Variance for Time:** | Source | df | SS | MS | F | P | |--------|----|--------|-------|-------|-----| | Brand | 3 | 365.28 | 121.76| 16.57 | 0.000 | | Error | 36 | 264.50 | 7.35 | | | | Total | 39 | 629.78 | | | | **Options for Conclusion:** 1. Fail to reject the null hypothesis and conclude that at least one mean differs from the other means. 2. Reject the null hypothesis and conclude that at least one mean differs from the other means. 3. Reject the null hypothesis and conclude that there is insufficient evidence to say that the means are not all equal. 4. Fail to reject the null hypothesis and conclude that there is insufficient evidence to say that the means are not all equal. **Explanation:** In this analysis of variance (ANOVA), we are given the following values: - **Degrees of freedom (df):** Represents the number of values that are free to vary. - **Sum of squares (SS):** Measures the total variability in the data. - **Mean square (MS):** An average of the squared deviations (SS divided by df). - **F-value:** A ratio of the variance explained by the model to the variance within the groups. - **P-value:** Indicates the probability of observing the F-value if the null hypothesis is true. Given the p-value of 0.000, which is less than α = 0.01, we can reject the null hypothesis and conclude that at least one brand mean differs from the others.
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