need help with my java code ### Java Programming: Finding the Largest Element in a Row of a Two-Dimensional ArrayAssume a two-dimensional integer array has been declared in the `main()` method.#### TaskCreate a Java method named `largestRowElement` that returns a `String` and has the following parameters:1. **A two-dimensional array** of type integer.2. **An integer** that represents the number of the row to be processed.#### Method FunctionalityThis method will find the largest element in the specified row and return a `String` containing the location and value of the largest element. **Sample Output:**```Largest element of row 0 is 25 in column 1```### Method Signature Example```javapublic String largestRowElement(int[][] array, int rowNum) { // Method implementation goes here}```**Explanation:**- `int[][] array`: Represents the two-dimensional integer array.- `int rowNum`: Represents the row number to be processed for finding the largest element. - The method will identify the largest element in the specified row, determine its column index, and return this information in a formatted string.### Example Usage of the Method```javapublic class Main { public static void main(String[] args) { int[][] array = { {10, 25, 3}, {7, 18, 5}, {14, 6, 30} }; Main obj = new Main(); String result = obj.largestRowElement(array, 0); System.out.println(result); // Output: Largest element of row 0 is 25 in column 1 } public String largestRowElement(int[][] array, int rowNum) { int largestElement = array[rowNum][0]; int columnIndex = 0; for (int i = 1; i < array[rowNum].length; i++) { if (array[rowNum][i] > largestElement) { largestElement = array[rowNum][i]; columnIndex = i; } } return "Largest element of row " + rowNum + " is " + largestElement + " in column " + columnIndex; }}```In this implementation:- We initialize `largestElement` to the first element in the specified row.- We iterate through the row to find the

A Java program is as follows, File name: “Sample.java” //Import necessary package import…

Assume a two-dimensional integer array has been declared in main(). Create a Java method named largestRowElement that returns a String and has the following parameters: A two-dimensional array of type integer An integer that represents the number of the row to be processed This method will find the largest element in the desired row and return a String containing the location and value of the largest element. A sample output would look similar to this: Largest element of row 0 is 25 in column 1

Assume a two-dimensional integer array has been declared in main(). Create a Java method named largestRowElement that returns a String and has the following parameters: A two-dimensional array of type integer An integer that represents the number of the row to be processed This method will find the largest element in the desired row and return a String containing the location and value of the largest element. A sample output would look similar to this: Largest element of row 0 is 25 in column 1

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Question

need help with my java code

### Java Programming: Finding the Largest Element in a Row of a Two-Dimensional Array

Assume a two-dimensional integer array has been declared in the `main()` method.

#### Task
Create a Java method named `largestRowElement` that returns a `String` and has the following parameters:

1. **A two-dimensional array** of type integer.
2. **An integer** that represents the number of the row to be processed.

#### Method Functionality
This method will find the largest element in the specified row and return a `String` containing the location and value of the largest element.

**Sample Output:**
```
Largest element of row 0 is 25 in column 1
```

### Method Signature Example
```java
public String largestRowElement(int[][] array, int rowNum) {
// Method implementation goes here
}
```

**Explanation:**
- `int[][] array`: Represents the two-dimensional integer array.
- `int rowNum`: Represents the row number to be processed for finding the largest element.
- The method will identify the largest element in the specified row, determine its column index, and return this information in a formatted string.

### Example Usage of the Method
```java
public class Main {
public static void main(String[] args) {
int[][] array = {
{10, 25, 3},
{7, 18, 5},
{14, 6, 30}
};

Main obj = new Main();
String result = obj.largestRowElement(array, 0);
System.out.println(result); // Output: Largest element of row 0 is 25 in column 1
}

public String largestRowElement(int[][] array, int rowNum) {
int largestElement = array[rowNum][0];
int columnIndex = 0;
for (int i = 1; i < array[rowNum].length; i++) {
if (array[rowNum][i] > largestElement) {
largestElement = array[rowNum][i];
columnIndex = i;
}
}
return "Largest element of row " + rowNum + " is " + largestElement + " in column " + columnIndex;
}
}
```

In this implementation:
- We initialize `largestElement` to the first element in the specified row.
- We iterate through the row to find the

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