Assume a small box (m = 222 g) slides along a frictionless ¼ circle track of radius R = 1.00 m onto a horizontal plane and into a spring of spring constant k = 55.5 N/m as shown in the following figure. The plane has a coefficient of friction that changes along the plane µ(x) = 0.200 x + 0.300. L in the figure below = 0.333 m. 1. What maximum distance does the spring compress through?

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### Physics Problem: Motion on a Frictional Plane with a Spring

**Problem Description:**
Assume a small box with a mass of 222 grams (0.222 kg) slides along a frictionless ¼ circle track of radius \( R = 1.00 \) meter onto a horizontal plane and into a spring. The spring has a spring constant \( k = 55.5 \, \text{N/m} \) as shown in the following figure. The plane has a coefficient of friction that changes along the plane described by the equation: 
\[ \mu(x) = 0.200 \, x + 0.300 \]
where \( x \) is the position along the plane. The distance \( L \) from the start of the horizontal plane to the point where the box first compresses the spring is 0.333 meters.

1. What maximum distance does the spring compress through?

**Figure Explanation:**
The figure depicts a situation where a small box slides along a curved track before moving onto a horizontal plane and compresses a spring. 

- The ¼ circular track has a radius \( R \) and is perfectly frictionless.
- \( x=y=R \) (the point where the circular track meets the horizontal plane).
- The coefficient of friction on the horizontal plane, \( \mu(x) \), varies with the distance \( x \) along the plane.
- The spring is depicted at the end of the horizontal plane.
- The path of the box is indicated, showing that it travels frictionlessly along the curved track, then slides with friction along the horizontal plane (indicated by hash marks) before encountering and compressing the spring (shown as a zigzag line).

The problem requires understanding motion under friction and Hooke’s law (spring force and compression) to determine how far the spring compresses when the box exerts force on it.
Transcribed Image Text:### Physics Problem: Motion on a Frictional Plane with a Spring **Problem Description:** Assume a small box with a mass of 222 grams (0.222 kg) slides along a frictionless ¼ circle track of radius \( R = 1.00 \) meter onto a horizontal plane and into a spring. The spring has a spring constant \( k = 55.5 \, \text{N/m} \) as shown in the following figure. The plane has a coefficient of friction that changes along the plane described by the equation: \[ \mu(x) = 0.200 \, x + 0.300 \] where \( x \) is the position along the plane. The distance \( L \) from the start of the horizontal plane to the point where the box first compresses the spring is 0.333 meters. 1. What maximum distance does the spring compress through? **Figure Explanation:** The figure depicts a situation where a small box slides along a curved track before moving onto a horizontal plane and compresses a spring. - The ¼ circular track has a radius \( R \) and is perfectly frictionless. - \( x=y=R \) (the point where the circular track meets the horizontal plane). - The coefficient of friction on the horizontal plane, \( \mu(x) \), varies with the distance \( x \) along the plane. - The spring is depicted at the end of the horizontal plane. - The path of the box is indicated, showing that it travels frictionlessly along the curved track, then slides with friction along the horizontal plane (indicated by hash marks) before encountering and compressing the spring (shown as a zigzag line). The problem requires understanding motion under friction and Hooke’s law (spring force and compression) to determine how far the spring compresses when the box exerts force on it.
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