Assume a hand has a 1.1 m shaft of bone with an average cross- sectional area of 25 ×10-5 m² . What is the amount of shortening when all o the body mass of 75 Kg is supported on this hand? A- Young's modulus= 1.8 x1010

Q: A 557-N force is applied to stretch a cable, 66-m long and has a cross-sectional area of 2.8 mm^2.…

A: Given that-Force, F=557 NLength, L=66marea, A=2.8 mm2Y=1×1011  N/m2We know that,Hook's law :…

Q: A 100 m long cable with a cross-sectional area of 1.0 mm² stretches by 5.0 cm when a force of 1,000…

A: Given data, Length of cable l = 100 m. Cross sectional area A=1 mm2=10-6 m2. Amount of cable…

Q: A circular rod of cross-sectional area 2 x 104m² has a tensile force of 80 kN app The stress in the…

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Q: s) The Young's modulus is a property of the material and does not depend on the size or shape of an…

A: The Young's Modulus of a material is a fundamental property of every material that cannot be…

Q: P k a P te

A: Shear stress; is a force that tends to cause material deformation by slippage along a plane or…

Q: 2. OSCOLPHYS2016 5.3.WA.038. MY NOTES ASK YOUR TEACHER During a wrestling match, a 116 kg wrestler…

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Q: Determine the Young's modulus of a 1.50 x 10^-1 m long tendon if it is stretched by 3.70 x10^-3 m by…

A:

Q: For safety in climbing, a mountaineer uses a nylon rope that is 65 m long and 1.4 cm in diameter.…

A: Given: Length of nylon rope L= 65 m long Diameter of rope , d = 1.4 cm Mass of climber, m= 85 kg…

Q: Consider a copper wire with cross-sectional area 4 mm?. The Young's modulus for copper is 1.1 × 1011…

A:

Q: A 557-N force is applied to stretch a cable, 66-m long and has a cross-sectional area of 2.8 mm^2.…

A: Given that-Force, F=557 NLength, L=66marea, A=2.8 mm2Y=1×1011  N/m2We know that,Hook's law FA=Y×∆LL…

Q: 7- A steel wire of length 1.5 mand diameterl mmis joined to an aluminumwire of identical dimensions…

A: “Since you have asked multiple question, we will solve the first question for you. If youwant any…

Q: 16. Biceps muscle. A relaxed biceps muscle requires a force of 25.0 N for an elongation of 3.0 cm;…

A: Detailed solution is given below:

Q: TUnOWng prUDIEms. A steel wire of diameter 1 mm can support a tension of 0.2 kN. Determine the…

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Q: A circular rod of cross-sectional area 2 x 10m² has a tensile force of 80 kN applied to it. The…

A:

Q: A wire of 2.0000 m length and 1.0 mm diameter is suspended from the ceiling. Hanging a 4.500 kg…

A: Original length L = 2.0000 m  Diameter of wire d = 1.0 mm  Radius of wire r = d/2 = 1.0 / 2 mm = 0.5…

Q: 10) Assume Young's Modulus for bone is 1.5E10 N/m². The bone breaks if stress greater than 1.5E8 N/…

A:

Q: A 557-N force is applied to stretch a cable, 66-m long and has a cross-sectional area of 2.8 mm^2.…

A: GivenForce, F=557 NLength, L=66marea, A=2.8 mm2 = 2.8×10-6 m2Y=1×1011  N/m2We know that,Hook's law…

Q: Assume a hand has a 1.4m shaft of bone with an average cross-sectional area of 3 [cm] ^2. What is…

A:

Q: For safety in climbing, a mountaineer uses a nylon rope that is 65 m long and 1.4 cm in diameter.…

A: In the question given the length of rope , diameter of rope , mass and change in the length and we…

Q: A wooden dowel is subjected to a shearing force of 715N on its top cylindrical face. If the dowel…

A: Shearing force F=715 N, diameter of dowel d=3cm (radius r=1.5cm), height of dowel h=11 cm and shear…

Q: A 24.0 m long aluminum cable with a cross-sectional area of 2.04 x 10-3 m2 is used to suspend a 3.20…

A: Given, Length L = 24.0 m             Area A = 2.04 × 10-3 m2            mass m = 3.20 × 103 kg…

Q: A 29.0 m long aluminum cable with a cross-sectional area of 2.01 x 10- m is used to suspend a 3.20 x…

A: The expression for young’s modulus of the material is, \Y=FAΔLL0ΔL=FL0AY=mgL0AY

Q: A 557-N force is applied to stretch a cable, 66-m long and has a cross-sectional area of 2.8 mm^2.…

A: Given that-Force, F=557 NLength, L=66marea, A=2.8 mm2Y=1×1011  N/m2

Q: Compression member AB is used to hold up the 250 x 340-mm rectangular plate. If the compressive…

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Q: The screwgate carabiner is left open as it is loaded by a rope as shown. Calculate the stress state…

A: Stress is defined as force per unit area.  σ=FA Where F is a force and A is cross-section area.

Q: P4. If the cross section of the femur at section a-a can be approximated as a hollow as shown,…

A: Maximum normal stress = 235.98 lb/in2 = 236 psi Detailed solution is given below: Please UPVOTE sir

Q: For safety in climbing, a mountaineer uses a nylon rope that is 65 m long and 1.3 cm in diameter.…

A:

Q: 2. A tall building with a cross-section A, a mass M and a Young's modulus Y has a height L on Earth.…

A: The mass of the building is M Area of cross section is A Young's modulus Y Height of the building is…

Q: Assume Young's modulus for bone is 1.50 x 1010 N/m2. The bone breaks if stress greater than o= 45844…

A: Young's modulus is Y= 1.5×10¹⁰  N/m²  Maximum stress is σ = 45844 N/m²  Effective radius of the bone…

Q: A 10.2 m long wire with a cross-sectional area of 0.126 cm2 stretches by 0.196 cm when a tensile…

A: The given values are, L=10.2 mA=0.126 cm2=0.126×10-4 m2∆L=0.196 cm=0.196×10-2 mF=6250 N

Q: Problems - Stress, Strain, and Young's Modulus P10-5. Zartan's vine, initially 6 m long, has a…

A: Given, Initially length of the vine, L=6m The Young's modulus, Y=0.1GN/m2Y=0.1×109N/m2 Stress,…

Q: For safety in climbing, a mountaineer uses a nylon rope that is 65 m long and 1.4 cm in diameter.…

A:

Q: A 557-N force is applied to stretch a cable, 66-m long and has a cross-sectional area of 2.8 mm^2.…

A: Given, Force F=557NL=66mA=2.8mm2Y=1.0×1011N/m2

Q: D$

A: Given that-Force, F=557 NLength, L=66marea, A=2.8 mm2Y=1×1011  N/m2We know that,Hook's law FA=Y×∆LL…

Q: Each section of the sky way is 1.7 km long, and each segment has a cross-sectional area of 117.4 m2.…

A: In this case, the length of each section of the skyway is given. And each has some cross-sectional…

Q: 14) An object put on a table with four legs. Both the table and the object together have the same…

A: Since we only answer up to 1 question, we’ll answer the first question. Please resubmit the…

Q: Calculate the force in member BG using a freebody diagram of the rigid member ABC. The orce is…

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Q: A solid body of mass 200kg hanging from a steel. Wire 5m long, and cross section 0.08 cm^2. The wire…

A:

Q: A 557-N force is applied to stretch a cable, 66-m long and has a cross-sectional area of 2.8 mm^2.…

A: Given that-Force, F=557 NLength, L=66marea, A=2.8 mm2Y=1×1011  N/m2We know that,Hook's law FA=Y×∆LL…