*Assume a density of 1.00g/mL and a specific heat of 4.184 J/g°C for these aqueous solutions. 3. The Heat of Solution for Ammonium Chloride 14.26a Mass of ammonium chloride 187.14% 311.25, Mass of empty, dry calorimeter Mass of calorimeter and water 20.8°C Initial temperature of water Ti Final temperature after dissolution Tf Calculations: Anmoniun chloride - 53.495/mol Specific heat of water= 4.184 J/6c Results: Heat absorbed per mole dissolved J/mole

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How do you find the heat absorbed per mole dissolved using this type of data?

*Assume a density of 1.00g/mL and a specific heat of 4.184 J/g°C for these aqueous solutions.
3. The Heat of Solution for Ammonium Chloride
14.26.
187.19
311.25g
Mass of ammonium chloride
Mass of empty, dry calorimeter
Mass of calorimeter and water
20.8°C
Initial temperature of water Ti
5.1°C
Final temperature after dissolution Tf
Calculations:
Ammoniun chloride= 53,495/ml
chloride = 53.495ml
%3D
Specific heat of water= 4.184 J/6°C
Results:
Heat absorbed per mole dissolved
J/mole
Transcribed Image Text:*Assume a density of 1.00g/mL and a specific heat of 4.184 J/g°C for these aqueous solutions. 3. The Heat of Solution for Ammonium Chloride 14.26. 187.19 311.25g Mass of ammonium chloride Mass of empty, dry calorimeter Mass of calorimeter and water 20.8°C Initial temperature of water Ti 5.1°C Final temperature after dissolution Tf Calculations: Ammoniun chloride= 53,495/ml chloride = 53.495ml %3D Specific heat of water= 4.184 J/6°C Results: Heat absorbed per mole dissolved J/mole
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