Assume 4-bit architecture. f(x,y) = 0 x=1010(-6) y=0001 (1) f(x,y) = 1 x=1010 y=0001 ZX = 1 0000 ZX = 1 0000 nx = 0 0000 nx = 1 1111 zy = 1 0000 zy = 1 0000 ny = 0 0000 ny = T 1111 f = 1 x+y=0000+0000= 0000 f = 1 x+y=1111+1111=01110 no= 0 f(x,y) = -1 x=1010 ZX = 0000 [0] y=0001 no = 1 1110 = 0001 [1] f(x,y) = X x=0100 y=0101 nx = zy = ny = f = no = ZX = nx = zy = ny = f = no =

Assume 4-bit architecture. f(x,y) = 0 x=1010(-6) y=0001 (1) f(x,y) = 1 x=1010 y=0001 ZX = 1 0000 ZX = 1 0000 nx = 0 0000 nx = 1 1111 zy = 1 0000 zy = 1 0000 ny = 0 0000 ny = T 1111 f = 1 x+y=0000+0000= 0000 f = 1 x+y=1111+1111=01110 no= 0 f(x,y) = -1 x=1010 ZX = 0000 [0] y=0001 no = 1 1110 = 0001 [1] f(x,y) = X x=0100 y=0101 nx = zy = ny = f = no = ZX = nx = zy = ny = f = no =

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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