An education researcher claims that at most 4% of working college students are employed as teachers or teaching assistants. In a random sample of 600 working college students, 6% are employed as teachers or teachingassistants. At a=0.10, is there enough evidence to reject the researcher's claim? Complete parts (a) through (e) below.Identify the rejection region(s). Select the correct choice below and fill in the answer box(es) to complete your choice.(Round to two decimal places as needed.)O A. The rejection regions are z<- 1.64 and z> 1.64O B. The rejection region is z<O C. The rejection region isO D. The rejection region is z>(c) Find the standardized test statistic z.(Round to two decimal places as needed.)(d) Decide whether to reject or fail to reject the null hypothesis and (e) interpret the decision in the context of the original claim.Rejectthe null hypothesis. There is not enough evidence to support the researcher's claim.((1)MoreNextTextbookCalculator7:56 PM64°F12/6/202123(99+P Type here to search10/05/17DG521 AUXF6F7PrtScInsertDeleteFBF9F10F11F12&89.BackspaceNumLockRY.UOPHomeFH.JKL0O5LLI

Given data sample proportion p̂ =0.06 sample size, n =600 population proportion,p=…

Answered: assistants At a= 0.10, is there enough…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In the figure below, what should you do when you are at the point in time where your sample outcome is represented by the red little dot in the upper right (where it savs "Out of control on this x-bar chart) u+30 Cut of cont on thishr chan ** UCLu+3a/n Target 99.7% sdouble-bar C LCL--3G/ Vn The "pooled" sd dev for samples of size n LSL . O Nothing: the point is between the USL and LSL. Adjust your process control limits. O Look for a "special cause" to pinpoint the reason the sample is at that point. O Adjust your specification limits.
Need the claim, hypothesis, crit value(s), rejection regions, d, Sd, t test, reject or fail to, and conclusion.
Reter to the mensured systolic and diastolic biood pressure mensurements of 40 andomty seiected meies and test the caimthet among men, there isa comeiation betveen systolie biood pressure and diestolic Diood pressure. Test for rank comreiation with a 0.05 sgnifcance level m Click the icon to view the blood pressure deta for men. Determine the nul and stemetive hypotheses for this test Choose the comect ansver below OA M0 O. M0 OD. HA0 Determine the coreietion coefficient -O Round to mree decimal piaces as nences) Derermine the ortical values of the comeistion coeftcient. Round to three decimal pisces as neeses. Usea comma to secarte anses as neeses) Chocse he comect enser below OA Faltoreject the nul typothesis. There is sufcient evidence to support the caimthet thereisa comiation beteen systolic and diastolic biood pressure in men. OB Reecthe nul hypothesis There is sufcient evidence to support the cam thet there is comeistion betveen systolic and diestolic biood pressure in men. OC.…
Find the margin of error for the given values of c, o, and n. c= 0.90, o = 3.4, n= 36 Click the icon to view a table of common critical values. E = (Round to three decimal places as needed.)
Let sample size n = 51. Find P (t > 4.92). a. 0.0005 < P (t > 4.92) < 0.001 b. 0.001 < P (t > 4.92) < 0.0025 c. P (t > 4.92) < 0.0005 d. P (t > 4.92) > 0.25
Find the margin of error for the given values of c, o, and n. c= 0.95, o = 3.3, n 64 Click the icon to view a table of common critical values. E = (Round to three decimal places as needed.)
T4
Describe the sampling distribution of p. Assume the size of the population is 20,000. n 800, p 0.356 Describe the shape of the sampling distribution of p. Choose the correct answer below. A. The shape of the sampling distribution of p is not normal because n s 0.05N and np(1 - p)< 10 В. The shape of the sampling distribution of p is approximately normal because ns0.05N and np(1 -p) 10 A С. The shape of the sampling distribution of p is approximately normal because ns0.05N and np(1 -p)2 10 D. The shape of the sampling distribution of p is not normal because ns 0.05N and np(1 -p)z 10. Determine the mean of the sampling distribution of p. (Round to three decimal places as needed.) HA р Determine the standard deviation of the sampling distribution of p. (Round to three decimal places as needed.) р
Find the margin of error for the given values of c, o, and n. c=0.90, o-2.8, n = 49 Click the icon to view a table of common critical values. E3D (Round to three decimal places as needed.)

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