Assignment Write RISC-V assembly code for bubble sort (without function calling). Assume that arr[5] = {6, 1, 3, 2, 7); starting at memory address 0x10000000. Pseudocode for bubble sort procedure bubbleSort (list: array of items) loop list.count; for i = 0 to loop-1 do: swapped false = for j = 0 to loop-1 do: /* compare the adjacent elements */ if list[j] > list[j+1] then /* swap them */ swap(list[i], list[j+1] ) swapped true end if end for /*if no number was swapped that means array is sorted now, break the loop. */ if (not swapped) then break end if

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Assignment
Write RISC-V assembly code for bubble sort (without function calling).
Assume that arr[5] = {6, 1, 3, 2, 7); starting at memory address 0x10000000.
Pseudocode for bubble sort
procedure bubbleSort( list: array of items)
loop list.count;
for i=0 to loop-1 do:
swapped false
for j = 0 to loop-1 do:
/* compare the adjacent elements */
if list[j] > list[j+1] then
/* swap them */
end if
end for
/*if no number was swapped that means
array is sorted now, break the loop. */
swap list [j], list[j+1] )
swapped true
if (not swapped) then
break
end if
end for
end procedure return list
Note that you will have to write 2 loops
Copy this starter code and continue writing your code in your .s file:
#arr = {6, 1, 3, 2, 7)
LI a0, 0x10000000 # start address
LI a2, 6
SB a2,0 (a0)
LI a2, 1
SB a2,4 (20)
LI a2, 3
SB a2, 8 (80)
LI a2, 2
SB a2, 12 (20)
LI a2, 7
SB a2, 16 (20)
#BEGIN YOUR CODE HERE
Transcribed Image Text:Assignment Write RISC-V assembly code for bubble sort (without function calling). Assume that arr[5] = {6, 1, 3, 2, 7); starting at memory address 0x10000000. Pseudocode for bubble sort procedure bubbleSort( list: array of items) loop list.count; for i=0 to loop-1 do: swapped false for j = 0 to loop-1 do: /* compare the adjacent elements */ if list[j] > list[j+1] then /* swap them */ end if end for /*if no number was swapped that means array is sorted now, break the loop. */ swap list [j], list[j+1] ) swapped true if (not swapped) then break end if end for end procedure return list Note that you will have to write 2 loops Copy this starter code and continue writing your code in your .s file: #arr = {6, 1, 3, 2, 7) LI a0, 0x10000000 # start address LI a2, 6 SB a2,0 (a0) LI a2, 1 SB a2,4 (20) LI a2, 3 SB a2, 8 (80) LI a2, 2 SB a2, 12 (20) LI a2, 7 SB a2, 16 (20) #BEGIN YOUR CODE HERE
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