Assignment Brief and Guidance: Activity 1 1.1. Solve the given mathematics problem using complex number theory. Consider the quadratic equation: z² -6z+13=0 i) Calculate the discriminant of the quadratic equation (D = b² -4ac) and determine whether it has real or complex roots. Explain your findings. ii) If the roots are complex, solve for the two complex roots (Z₁ and Z2) using the quadratic formula: -b±√D Z 2a iii) iv) Express the complex roots (Z₁ and Z2) in both rectangular form (x+yi) and polar form (re¹º), where r is the magnitude of the complex number and 0 is the argument. Discuss the geometric interpretation of the complex roots in the complex plane.

Advanced Engineering Mathematics
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ISBN:9780470458365
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Assignment Brief and Guidance:
Activity 1
1.1.
Solve the given mathematics problem using complex number theory.
Consider the quadratic equation: z² -6z+13=0
i) Calculate the discriminant of the quadratic equation (D = b² -4ac) and determine
whether it has real or complex roots. Explain your findings.
ii)
If the roots are complex, solve for the two complex roots (Z₁ and Z2) using the quadratic
formula:
-b±√D
Z
2a
iii)
iv)
Express the complex roots (Z₁ and Z2) in both rectangular form (x+yi) and polar form
(re¹º), where r is the magnitude of the complex number and 0 is the argument.
Discuss the geometric interpretation of the complex roots in the complex plane.
Transcribed Image Text:Assignment Brief and Guidance: Activity 1 1.1. Solve the given mathematics problem using complex number theory. Consider the quadratic equation: z² -6z+13=0 i) Calculate the discriminant of the quadratic equation (D = b² -4ac) and determine whether it has real or complex roots. Explain your findings. ii) If the roots are complex, solve for the two complex roots (Z₁ and Z2) using the quadratic formula: -b±√D Z 2a iii) iv) Express the complex roots (Z₁ and Z2) in both rectangular form (x+yi) and polar form (re¹º), where r is the magnitude of the complex number and 0 is the argument. Discuss the geometric interpretation of the complex roots in the complex plane.
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