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Assignment 1 on False Regula Method of the problem in exercise 5.24. Write a code in MATLAB for the False position method or use the algorithm in 5.15. Use es = 0.005 as stopping criteria. Show the output in a table. Provide problem in exercise 5.24

Assignment 1 on False Regula Method of the problem in exercise 5.24. Write a code in MATLAB for the False position method or use the algorithm in 5.15. Use es = 0.005 as stopping criteria. Show the output in a table. Provide problem in exercise 5.24

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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MATLAB Assignment 1 on False Regula Method of the problem in exercise 5.24. Write a code in MATLAB for the False position method or use the algorithm in 5.15.

Use es = 0.005 as stopping criteria. Show the output in a table.

  • Provide problem in exercise 5.24

5.24 Develop a subprogram for the false-position method that min- imizes function evaluations in a fashion similar to Fig. 5.11. Deter- mine the number of function evaluations (n) per total iterations. Test the program by duplicating Example 5.6.
Transcribed Image Text:5.24 Develop a subprogram for the false-position method that min- imizes function evaluations in a fashion similar to Fig. 5.11. Deter- mine the number of function evaluations (n) per total iterations. Test the program by duplicating Example 5.6.
FUNCTION ModFalsePos(xl, xu, es, imax, xr, iter, ea) FIGURE 5.15 Pseudocode for the modified iter = 0 false position method. fl = f(x1) fu = f(xu) DO xrold = xr xr = Xu - fu * (xl – xu) / (fl - fu) fr = f(xr) iter = iter + 1 IF xr <> 0 THEN ea = Abs( (xr - xrold) / xr) * 100 END IF test = fl * fr IF test < 0 THEN XU = xr fu = f(xu) iu = 0 il = 11 + 1 If il 2 2 THEN f1 = fl / 2 ELSE IF test >O THEN x) = xr fl = f(x1) il = 0 iu = iu + 1 IF iu 2 2 THEN fu = fu / 2 ELSE ea = 0 END IF IF ea < es OR iter z imax THEN EXIT END DO ModFalsePos = xr End MODFALSEPOS
Transcribed Image Text:FUNCTION ModFalsePos(xl, xu, es, imax, xr, iter, ea) FIGURE 5.15 Pseudocode for the modified iter = 0 false position method. fl = f(x1) fu = f(xu) DO xrold = xr xr = Xu - fu * (xl – xu) / (fl - fu) fr = f(xr) iter = iter + 1 IF xr <> 0 THEN ea = Abs( (xr - xrold) / xr) * 100 END IF test = fl * fr IF test < 0 THEN XU = xr fu = f(xu) iu = 0 il = 11 + 1 If il 2 2 THEN f1 = fl / 2 ELSE IF test >O THEN x) = xr fl = f(x1) il = 0 iu = iu + 1 IF iu 2 2 THEN fu = fu / 2 ELSE ea = 0 END IF IF ea < es OR iter z imax THEN EXIT END DO ModFalsePos = xr End MODFALSEPOS
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