Assign to maxSum the max of (numA, numB) PLUS the max of (numY, numZ). Use just one statement. Hint: Call findMax() twice in an expression. import java.util.Scanner; public class SumOfMax {public static double findMax(double num1, double num2) {double maxVal; // Note: if-else statements need not be understood to// complete this activityif (num1 > num2) { // if num1 is greater than num2,maxVal = num1; // then num1 is the maxVal.}else { // Otherwise,maxVal = num2; // num2 is the maxVal.}return maxVal;} public static void main(String [] args) {Scanner scnr = new Scanner(System.in);double numA;double numB;double numY;double numZ;double maxSum; numA = scnr.nextDouble();numB = scnr.nextDouble();numY = scnr.nextDouble();numZ = scnr.nextDouble(); /* Your solution goes here */ System.out.print("maxSum is: " + maxSum);}}
Assign to maxSum the max of (numA, numB) PLUS the max of (numY, numZ). Use just one statement. Hint: Call findMax() twice in an expression.
import java.util.Scanner;
public class SumOfMax {
public static double findMax(double num1, double num2) {
double maxVal;
// Note: if-else statements need not be understood to
// complete this activity
if (num1 > num2) { // if num1 is greater than num2,
maxVal = num1; // then num1 is the maxVal.
}
else { // Otherwise,
maxVal = num2; // num2 is the maxVal.
}
return maxVal;
}
public static void main(String [] args) {
Scanner scnr = new Scanner(System.in);
double numA;
double numB;
double numY;
double numZ;
double maxSum;
numA = scnr.nextDouble();
numB = scnr.nextDouble();
numY = scnr.nextDouble();
numZ = scnr.nextDouble();
/* Your solution goes here */
System.out.print("maxSum is: " + maxSum);
}
}
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