ASSESSMENT PROBLEMS Objective 5-Understand Thévenin and Norton equivalents 4.16 Find the Thévenin equivalent circuit with re- spect to the terminals a, b for the circuit shown. Juanio erit Answer: Vab= VTh = 64.8 V, RTh = 60. 72 V 12 Ω 5Ω - 8 Ω www Σ 20 Ω

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**Assessment Problems**

### Objective 5—Understand Thévenin and Norton equivalents

**4.16** Find the Thévenin equivalent circuit with respect to the terminals a, b for the circuit shown.

- **Answer:** \( V_{ab} = V_{Th} = 64.8 \, V, \, R_{Th} = 6 \, \Omega. \)

**Circuit Diagram Explanation:**

The circuit depicted consists of:

- A 72 V voltage source.
- Three resistors connected in a combination of series and parallel:
  - A 12 Ω resistor in series with the 72 V source.
  - A 5 Ω resistor in series with the 12 Ω resistor.
  - An 8 Ω resistor connected in series to both the 12 Ω and 5 Ω resistors.
  - A 20 Ω resistor connected in parallel with the 5 Ω resistor.

This setup forms a complex arrangement where the equivalent Thévenin voltage (\(V_{Th}\)) and resistance (\(R_{Th}\)) with respect to terminals a and b are calculated as 64.8 V and 6 Ω, respectively.
Transcribed Image Text:**Assessment Problems** ### Objective 5—Understand Thévenin and Norton equivalents **4.16** Find the Thévenin equivalent circuit with respect to the terminals a, b for the circuit shown. - **Answer:** \( V_{ab} = V_{Th} = 64.8 \, V, \, R_{Th} = 6 \, \Omega. \) **Circuit Diagram Explanation:** The circuit depicted consists of: - A 72 V voltage source. - Three resistors connected in a combination of series and parallel: - A 12 Ω resistor in series with the 72 V source. - A 5 Ω resistor in series with the 12 Ω resistor. - An 8 Ω resistor connected in series to both the 12 Ω and 5 Ω resistors. - A 20 Ω resistor connected in parallel with the 5 Ω resistor. This setup forms a complex arrangement where the equivalent Thévenin voltage (\(V_{Th}\)) and resistance (\(R_{Th}\)) with respect to terminals a and b are calculated as 64.8 V and 6 Ω, respectively.
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