Aspen Plastics produces plastic bottles to customer order. The quality inspector randomly selects four bottles from the bottle machine and measures the outside diameter of the bottle neck, a critical qualitydimension that determines whether the bottle cap will fit properly. The dimensions (in) from the last six samples areBottleSample123410578057906070587200020578050505000615058305900.00056Click the icon to view the table of factors for calculating three-sigma limits for the x-chart and R-chart3062400020580057206000.601Suppose that the specification for the bottle neck diameter is 0 600+0 050 in and the population standard deviation is 0.012 ina. What is the process capability index?The Go is (Enter your response rounded to hep decimal places)406100.5820.57205900 6000.504O

The process capability index is the minimum specification limit. The centre value of the…

Answered: Aspen Plastics produces plastic bottles…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use R code, place the steps and screenshots of the procedure From the following data of the diameter of a particle in (μm) Calculate: Sample mean, Sample standard deviationHistogram (Frequency vs diameter), Histogram (probability density vs diameter)Curves (equation and graph) that fit the graphs and their explanation Diameter (μm) 2 2.6 1.2 1.8 0.8 2 1.4 1.4 1.4 1.8 1.4 1.4 1.4 0.6 1.2 1.2 41.4 1.4 2.4 1.4 2 2.4 1.8 1.4 2 1.8 2 1.8 0.8 2.2 2.8 2.8 4.6 2 1.4 2.4 1.2 1.4 1.2 5 1.4 1.2 2 0.8 1.4 1.8 1.2 2 1.4 1.4 1.8 2.6
In constructing a control chart for the proportions of defective coins, a researcher calculates LCL to be 0.000025. What does "LCL" represent, and how should that value be adjusted? www Choose the correct answer below. OA. "LCL" represents the lower control limit. Since - 0.000025 is less than 0.05, this is an unusual LCL and the researcher should adjust the LCL to a value of - 1. OB. "LCL" represents the lower control limit. Since -0.000025 is less than 0 and proportions can never be less than zero, the researcher should adjust the LCL to a value of 0. OC. "LCL" represents the least common logarithm. Since - 0.000025 is less than 0.05, this is an unusual LCL and the researcher should adjust the LCL to a value of - 1. OD. "LCL" represents the least common logarithm. Since - 0.000025 is less than 0 and it is not possible to take the logarithm of a negative number, the researcher should adjust the LCL to a value of 0.
Define a suitable population, variable/s, and the parameter of interest for the following study: A market researcher wishes to determine the market share of the four leading brands of cereal among children in Davao City who are 12 years old or younger What is the Population? Variable/s? K Parameter of Interest?
A stratified sample is sometimes recommended when?
Calculate the 1. Population and sample skewness, add interpretation 2. Exact and excess sample kurtosis, add interpretation
Mean= Median= Mode= Range=
Type size Mean S.D. I 10 136.7 4.5 II 15 138.3 4.6 7. | find the 98% econfidence interval for the difference of mean fabric strengths for the two types using a pooled interval. Interpret your answer.
What is the scale of measurement (type of variable) of the following variable? Pathologic Tumor Size (cm)
Please help
N To determine if their 1.50 inch steel handles are properly adjusted, Smith & Johnson Industries has decided to use an X-Chart which uses the range to estimate the variability in the sample. Answe Step 2 of 7: What is the Upper Control Limit? Round your answer to three decimal places. Table 1 2 Control Chart Select the Copy Table button to copy all values. To select an entire row or column, either click on the row or column header or use the Shift and arrow keys. To find the average of the selected cells, select the Average Values button. Copy Table Average Values The average of the selected cell(s) is 1.460. Copy Value 34 Period obs1 obs2 obs3 obs4 obs5 obs6 Sample Mean Sample Range 1.46 1.50 1.46 1.53 1.55 1.54 1.5067 1.54 1.45 1.49 1.53 1.46 1.52 1.4983 1.50 1.54 1.47 1.51 1.45 1.47 1.4900 1.49 1.52 1.53 1.47 1.50 1.53 1.5067 5 1.46 1.45 1.49 1.4850 6 1.51 1.51 1.52 1.5117 7 1.53 1.50 1.47 1.54 1.5050 8 1.50 1.5067 1.54 1.50 1.47 1.46 1.54 1.53 1.53 1.46 1.51 1.52 1.50 1.47 1.54…
Example 19.13 A company used three different methods of advertising its product in three cities. It later found the increased sales (in thousand rupees) in identical retail outlets in the three cities as follows: City A: City B: City C: 70 58 60 45 55 62 89 72 65 57 48 55 75 68 45 52 63 53 59 71 70 63 60 58 75
You are required to find any case study or research data that have been collected from the first party. The data that you gathered need to be presented as a grouped data with 10 classes. (You may use Google Image engine in this process) a) Based on the data above,i. calculate all type of Measure Central Tendency (mean, median, mode, Q1 & Q3) ii. calculate all type of Measure of Dispersion. (std. dev, variance, interquartile range) b) Construct a histogram and frequency polygon for the above data. (You are required to use Microsoft excel to construct the graphs)c) Interpret the graph.

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