a)Solve the following system of equations. Let z be the parameter. 2x+3y−z =1 3x+5y+z =4
a)Solve the following system of equations. Let z be the parameter. 2x+3y−z =1 3x+5y+z =4
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter9: Systems Of Linear Equations
Section9.7: Puzzle Problems
Problem 19P
Related questions
Question
a)Solve the following system of equations. Let z be the parameter.
|
2x+3y−z
|
=1
|
|
3x+5y+z
|
=4
|
b)For the following system of equations in echelon form, tell how many solutions there are in nonnegative integers.
|
x+3y+z
|
=88
|
|
7y+2z
|
=56
|
c) For the following system of equations in echelon form, tell how many solutions there are in nonnegative integers.
|
2x+3y+2z
|
=80
|
|
y−2z
|
=20
|
d) A person has $22,000invested in stock A and stock B. Stock A currently sells for $40
a share and stock B sells for $90a share. If stock B triples
in value and stock A goes up 50%, his stock will be worth
a share and stock B sells for $90a share. If stock B triples
in value and stock A goes up 50%, his stock will be worth
$60,000.
How many shares of each stock does he own?Expert Solution
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