Chemistry HW，how to calculate mass % ？ AsO43+3 Ag+=> Ag3AsO4 (0)The arsenate is converted into a solid (Ag3AsO4 (s)). If the mass of solid produced is known, wecan calculate the mass percent of arsenic in the 1.00 kg soil sample.Soil Sample 1Volume of soilVolume of 1 MMass of Ag3AsO4 (g)Mass % of As in SoilSample (mL)AGNO3 (mL)Sample100.0020.000.370024 g50.0020.000.185012 gSoil Sample 2Mass of Ag3AsO4 (g) Mass % of As in SoilSampleVolume of soilVolume of 1 MSample (mL)AGNO: (mL)100.0020.000.231265 g50.0020.000.115633 g

Given,Moles of Ag3AsO4 = 0.370024g Ag3AsO4 × 1mol Ag3AsO4462.5g Ag3AsO4 = 8.0 × 10-4molMoles of Ag3AsO4 = Moles of AsMass of As = 8.0 × 10-4mol As × 75g1mol As = 0.06g%mass = Mass of AsMass of soil sample ×100 = 0.06g1000g ×100 = 0.006% Moles of Ag3AsO4 = 0.185012g Ag3AsO4 × 1mol Ag3AsO4462.5g Ag3AsO4 = 4.0 × 10-4molMoles of Ag3AsO4 = Moles of AsMass of As = 4.0 × 10-4mol As × 75g1mol As = 0.03g%mass = Mass of AsMass of soil sample ×100 = 0.03g1000g ×100 = 0.003%Moles of Ag3AsO4 = 0.231265g Ag3AsO4 × 1mol Ag3AsO4462.5g Ag3AsO4 = 5.0 × 10-4molMoles of Ag3AsO4 = Moles of AsMass of As = 5.0 × 10-4mol As × 75g1mol As = 0.0375g%mass = Mass of AsMass of soil sample ×100 = 0.0375g1000g ×100 = 0.00375% Moles of Ag3AsO4 = 0.115633g Ag3AsO4 × 1mol Ag3AsO4462.5g Ag3AsO4 = 4.0 × 10-4molMoles of Ag3AsO4 = Moles of AsMass of As = 4.0 × 10-4mol As × 75g As1mol As = 0.01875g%mass = Mass of AsMass of soil sample ×100 = 0.03g1000g ×100 = 0.001875%