### Based on the figure, select **all** true equations.There is a right triangle ABC with one angle of 48° at vertex A. The sides of the triangle are labeled as follows:- Side opposite the 48° angle (BC) is labeled \( a \).- Side adjacent to the 48° angle (AC) is labeled \( b \).- Hypotenuse (AB) is labeled \( c \).The given options are:- **A** \( \tan(48°) = \dfrac{a}{b} \)- **B** \( \sin(48°) = \dfrac{b}{c} \)- **C** \( \cos(42°) = \dfrac{b}{c} \)- **D** \( \sin(42°) = \dfrac{b}{c} \)- **E** \( \tan(42°) = \dfrac{b}{a} \)- **F** \( \cos(48°) = \dfrac{b}{c} \)To solve this problem, we need to use the definitions of trigonometric functions:- \( \sin(\theta) = \dfrac{\text{opposite}}{\text{hypotenuse}} \)- \( \cos(\theta) = \dfrac{\text{adjacent}}{\text{hypotenuse}} \)- \( \tan(\theta) = \dfrac{\text{opposite}}{\text{adjacent}} \)For the given triangle:- \( \sin(48°) = \dfrac{a}{c} \)- \( \cos(48°) = \dfrac{b}{c} \)- \( \tan(48°) = \dfrac{a}{b} \)Additionally, we can use the complementary angle property (90° - θ) and the definitions above:- \( \sin(42°) = \cos(48°) = \dfrac{b}{c} \)- \( \cos(42°) = \sin(48°) = \dfrac{a}{c} \)- \( \tan(42°) = \dfrac{1}{\tan(48°)} = \dfrac{b}{a} \)Based on these relationships, **A**, **C**, **D**, **

Name: ### Based on the figure, select **all** true equations.There is a rig
Uploaded: 2024-03-20T06:46:55.000Z
Channel: Bartleby
Description: ### Based on the figure, select **all** true equations.There is a right triangle ABC with one angle of 48° at vertex A. The sides of the triangle are labeled as follows:- Side opposite the 48° angle (BC) is labeled \( a \).- Side adjacent to the 48°