Ascorbic acid (vitamin C) contains C, H, and O. In one combustion analysis, 5.24 g of ascorbic acid yields 7.86 g CO2 and 2.14 g H,0. Calculate the empirical formula and molecular formula of ascorbic acid given that its molar mass is about 176 g/mol. Add subscripts to complete the formulas. Empirical formula: CHO : Molecular formula: CHO :

Q: Combustion analysis of naphthalene, a hydrocarbon used in mothballs, produced 8.80 g CO2 and 1.44g…

A: The empirical formula is to be calculated. Provided that naphthalene produced 8.80 g CO2 and 1.44 g…

Q: When 1.615 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 5.545 grams…

A: The molecular formula is a formula generated from molecules that represents the total number of…

Q: Ascorbic acid (vitamin C) contains C, H, and O. In one combustion analysis, 5.24 g of ascorbic acid…

A: Given data contains, Mass of carbon dioxide is 7.86g. Mass of water is 2.14g.

Q: Combustion analysis of a hydrocarbon produced 33.01 g CO2 and 13.51 g H2O. Calculate the empirical…

A: Solution Given data, The amount of CO2 = 33.01g The amount of H2O = 13.52g Number of moles of…

Q: Combustion of a hydrocarbon in a limited supply of air produces COCO in addition to CO2CO2 and…

A: You don't provide the amount of water. But based on my experience put this value. If this value is…

Q: Combustion analysis of a hydrocarbon produced 33.01 g CO2 and 13.51 g H2O. Calculate the empirical…

A:

Q: Combustion analysis of a hydrocarbon produced 33.01 g of CO2 and 27.03 g of H2O. Calculate the…

A: Given : Mass of CO2 produced = 33.01 g And mass of H2O produced = 27.03 g Since the compound is a…

Q: The empirical formula for xylene is C4H5(l), and its molar mass is 106 g/mol. What is the molecular…

A: Given :-  Molar mass of xylene = 106 g/mol  Empirical formula = C4H5   To determine :-  Its…

Q: Combustion analysis of a hydrocarbon produced 33.01 g CO2 and 4.83 g H2O. What is the empirical…

A: Given : Mass of CO2 produced = 33.01 g Mass of H2O produced = 4.83 g And the compound is…

Q: A 4.866 gram sample of an organic compound containing only C, H, and O is analyzed by combustion…

A: Since all the carbon in carbon dioxide and hydrogen in water is coming from the organic compound…

Q: The foul odor of rancid butter is due largely to butyric acid, a compound containing carbon,…

A:

Q: A compound contains only C, H, and N. Combustion of 35.0 mg of the compound produces 54.9 mg CO2 and…

A:

Q: When 2.115 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 6.637 grams…

A: First of all we calculate the mass of Carbon in Carbon dioxide and mass of Hydrogen in water. Then…

Q: Isopropyl alcohol, sold as rubbing alcohol, is composed of C, H, and O. Combustion of 0.255 g of…

A: 1 mole of CO2 (44 g) contains 1 mole of C (12 g) and two moles of oxygen. The amount of Carbon and…

Q: Combustion analysis of a hydrocarbon produced 33.01 g of CO2 and 27.02 g of H2O. Calculate the…

A:

Q: Combustion analysis of a hydrocarbon produced 33.01 g CO2 and 4.83 g H2O. Calculate the empirical…

A: Given : Mass of CO2 produced = 33.01 g Mass of H2O produced = 4.83 g And the compound is…

Q: When 4.993 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 15.67 grams…

A:

Q: A 8.861 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis…

A: The simplest formula of any particular compound is categorized a empirical formula which consists of…

Q: A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68 mg of the compound yields…

A: The number of moles of the compound can be calculated by dividing the given mass of the compound by…

Q: A sample of a certain organic acid has a mass of 5.000 g.  Elemental analysis of this compound found…

A: Total mass of the sample of organic acid = 5 g Amount of C = 1.334 g Amount of O = 3.554 g Amount of…

Q: A molecule has an empirical formula of Ch2. 1.34 moles of the compound give 530.76 g of CO2 upon…

A: Given : We have to calculate the molecular formula.

Q: A compound contains only C, H, and N. Combustion of 35.0 mg of the compound produces 53.0 mg CO2 and…

A: Given: Compound contains only C, H and N. Mass of compound combusted = 35.0 mg = 0.035 g.…

Q: Tartaric acid is the white, powdery substance that coats sour candies such as Sour Patch Kids.…

A:

Q: A compound contains only C, H, and N. Combustion of 35.0 mg of the compound produces 33.5 mg CO2…

A: Given: compound contains only C, H, and N mass of compound = 35 mg mass of CO2 produced = 33.5 mg…

Q: Menthol is a flavoring agent extracted from peppermint oil. It contains C, H, and O. In one…

A: The combustion of menthol is given by

Q: s 7.86 g CO2 and 2.14 g H20. Calculate the empirical formula and molecular ula of acid given that…

A: Mass of acid = 5.24 g Mass of CO2 = 7.86 g Mass of H2O = 2.14 g

Q: A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of 0.157 g sample of the…

A:

Q: A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68 mg of the compound yields…

A:

Q: Combustion analysis of 2.796 g of an unknown compound containing carbon, hydrogen, and oxygen…

A:

Q: Combustion analysis of a hydrocarbon produces 33.01 g CO2 and 13.51 g H2O. Calculate the empirical…

A: Given: Combustion analysis gives 33.01 g CO2 and 13.51 g H2O.

Q: Combustion analysis of 63.8 mg of a C, H, and O containing compound produced 145.0 mg of CO2 and…

A: Empirical formula is the simplest ratio of the elements present in the exact molecular formula.…

Q: Combustion analysis of naphthalene, a hydrocarbon used in mothballs, produced 8.80 g CO2 and 1.44 g…

A: Use molar mass of to calculated the moles of C and H

Q: Combustion analysis of 1.200 g of an unknown compound containing carbon, hydrogen, and oxygen…

A: molar mass of CO2 = 44 g/molmolar mass of carbon = 12 g/mol1 CO2 has 1 C in itmolar mass of H2O = 18…

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.