As shown in the figure below, a horizontal alignment consists of two tangent lines smoothened by a horizontal curve. A 4% superelevation rate is designed for the horizontal curve and the superelevation runoff length is 291 feet. The normal cross-section is shown in the figure below, where both left and right sections have 2% slopes for drainage. Calculate the tangent runout length. (Round to the nearest foot and fill in the blank with a number only.) PC Sta 20+ 30.00 R R +2% PT Rotation axis -2%

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Question 13
As shown in the figure below, a horizontal alignment consists of two tangent lines
smoothened by a horizontal curve. A 4% superelevation rate is designed for the horizontal
curve and the superelevation runoff length is 291 feet. The normal cross-section is shown
in the figure below, where both left and right sections have 2% slopes for drainage.
Calculate the tangent runout length.
(Round to the nearest foot and fill in the blank with a number only.)
PC
Sta 20+30.00
R
+2%
R
PT
Rotation axis
-2%
Transcribed Image Text:Question 13 As shown in the figure below, a horizontal alignment consists of two tangent lines smoothened by a horizontal curve. A 4% superelevation rate is designed for the horizontal curve and the superelevation runoff length is 291 feet. The normal cross-section is shown in the figure below, where both left and right sections have 2% slopes for drainage. Calculate the tangent runout length. (Round to the nearest foot and fill in the blank with a number only.) PC Sta 20+30.00 R +2% R PT Rotation axis -2%
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