As shown in the figure below, a bullet is fired at and passes through a piece of target paper suspended by a massless string. The bullet has a mass m, a speed v before the collision with the target, a speed (0.526)v after passing through the target. M (a) Before collision (b) After collision The collision is inelastic and during the collision, the amount of energy lost is equal to a fraction [(0.383)KE, BC) of the kinetic energy of the bullet before the collision. Determine the mass M of the target and the speed V of the target the instant after the collision in terms of the mass m of the bullet and speed v of the bullet before the collision. (Express your answers to at least 3 decimals.) M

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As shown in the figure below, a bullet is fired at and passes through a piece of target paper suspended by a massless string. The bullet has a mass m, a speed v before the collision with the target,
a speed (0.526)v after passing through the target.
DLAC
(a) Before collision
(b) After collision
The collision is inelastic and during the collision, the amount of energy lost is equal to a fraction [(0.383)KE, Bc] of the kinetic energy of the bullet before the collision. Determine the mass M of the
target and the speed V of the target the instant after the collision in terms of the mass m of the bullet and speed v of the bullet before the collision. (Express your answers to at least 3 decimals.)
M
Transcribed Image Text:As shown in the figure below, a bullet is fired at and passes through a piece of target paper suspended by a massless string. The bullet has a mass m, a speed v before the collision with the target, a speed (0.526)v after passing through the target. DLAC (a) Before collision (b) After collision The collision is inelastic and during the collision, the amount of energy lost is equal to a fraction [(0.383)KE, Bc] of the kinetic energy of the bullet before the collision. Determine the mass M of the target and the speed V of the target the instant after the collision in terms of the mass m of the bullet and speed v of the bullet before the collision. (Express your answers to at least 3 decimals.) M
Expert Solution
Step 1

Given data, 

νinitial(bullet)=ννfinal(bullet)=0.526ννinitial(Paper)=0νfinal(Paper)=Vmbullet=mmpaper=MLoss KE=0.383 KE

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