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As shown in the figure below, a ball is suspended vertically (at rest) from a pivot point by a strong lightweight cord. When a wind of constant force F is incident on the ball, it swings upward to some height above the starting point. The maximum height H, L = 0.770 m. obtained is a function of the force F. The mass of the ball is m = 0.140 kg and the length of the cord is max Pivot Pivot L L H m (a) Find an expression for H, max (in m) as a function of F. You may use any of the given variables and g. (Do not substitute numerical values; use variables only.) 1 mg Hmax V F² + (mg)² (b) Evaluate H (in m) for F = 1.00 N. max 0.148 (c) Evaluate H. (in m) for F = 10.0 N. max 0.665 (d) How does H. max behave as F approaches zero? (Enter your answer in m.) As F → 0, H → 0 m. (е) How does H. max behave as F approaches infinity? (Enter your answer in m.) As F → 0, H → 0.77 m. (f) Now, instead of releasing the ball from the vertical position, the ball is positioned at its equilibrium height Hegt such that when it is released at this height, it hangs motionless. Determine an expression for the equilibrium height, Hoe as a function of F. You may use any of the given variables and g. (Do not substitute numerical values; use variables only.) H eg (g) Evaluate the equilibrium height (in m) for F = 10.0 N. (h) Evaluate the equilibrium height (in m) for F going to infinity. m

As shown in the figure below, a ball is suspended vertically (at rest) from a pivot point by a strong lightweight cord. When a wind of constant force F is incident on the ball, it swings upward to some height above the starting point. The maximum height H, L = 0.770 m. obtained is a function of the force F. The mass of the ball is m = 0.140 kg and the length of the cord is max Pivot Pivot L L H m (a) Find an expression for H, max (in m) as a function of F. You may use any of the given variables and g. (Do not substitute numerical values; use variables only.) 1 mg Hmax V F² + (mg)² (b) Evaluate H (in m) for F = 1.00 N. max 0.148 (c) Evaluate H. (in m) for F = 10.0 N. max 0.665 (d) How does H. max behave as F approaches zero? (Enter your answer in m.) As F → 0, H → 0 m. (е) How does H. max behave as F approaches infinity? (Enter your answer in m.) As F → 0, H → 0.77 m. (f) Now, instead of releasing the ball from the vertical position, the ball is positioned at its equilibrium height Hegt such that when it is released at this height, it hangs motionless. Determine an expression for the equilibrium height, Hoe as a function of F. You may use any of the given variables and g. (Do not substitute numerical values; use variables only.) H eg (g) Evaluate the equilibrium height (in m) for F = 10.0 N. (h) Evaluate the equilibrium height (in m) for F going to infinity. m

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Hey guys, ive done a-e but im lost on what to do on f-h help please :)

As shown in the figure below, a ball is suspended vertically (at rest) from a pivot point by a strong lightweight cord. When a wind of constant force F is incident on the ball, it swings upward to some height above the starting point. The maximum height H, L = 0.770 m. obtained is a function of the force F. The mass of the ball is m = 0.140 kg and the length of the cord is max Pivot Pivot L L H m (a) Find an expression for H, max (in m) as a function of F. You may use any of the given variables and g. (Do not substitute numerical values; use variables only.) 1 mg Hmax V F² + (mg)² (b) Evaluate H (in m) for F = 1.00 N. max 0.148 (c) Evaluate H. (in m) for F = 10.0 N. max 0.665 (d) How does H. max behave as F approaches zero? (Enter your answer in m.) As F → 0, H → 0 m. (е) How does H. max behave as F approaches infinity? (Enter your answer in m.) As F → 0, H → 0.77 m. (f) Now, instead of releasing the ball from the vertical position, the ball is positioned at its equilibrium height Hegt such that when it is released at this height, it hangs motionless. Determine an expression for the equilibrium height, Hoe as a function of F. You may use any of the given variables and g. (Do not substitute numerical values; use variables only.) H eg (g) Evaluate the equilibrium height (in m) for F = 10.0 N. (h) Evaluate the equilibrium height (in m) for F going to infinity. m
Transcribed Image Text:As shown in the figure below, a ball is suspended vertically (at rest) from a pivot point by a strong lightweight cord. When a wind of constant force F is incident on the ball, it swings upward to some height above the starting point. The maximum height H, L = 0.770 m. obtained is a function of the force F. The mass of the ball is m = 0.140 kg and the length of the cord is max Pivot Pivot L L H m (a) Find an expression for H, max (in m) as a function of F. You may use any of the given variables and g. (Do not substitute numerical values; use variables only.) 1 mg Hmax V F² + (mg)² (b) Evaluate H (in m) for F = 1.00 N. max 0.148 (c) Evaluate H. (in m) for F = 10.0 N. max 0.665 (d) How does H. max behave as F approaches zero? (Enter your answer in m.) As F → 0, H → 0 m. (е) How does H. max behave as F approaches infinity? (Enter your answer in m.) As F → 0, H → 0.77 m. (f) Now, instead of releasing the ball from the vertical position, the ball is positioned at its equilibrium height Hegt such that when it is released at this height, it hangs motionless. Determine an expression for the equilibrium height, Hoe as a function of F. You may use any of the given variables and g. (Do not substitute numerical values; use variables only.) H eg (g) Evaluate the equilibrium height (in m) for F = 10.0 N. (h) Evaluate the equilibrium height (in m) for F going to infinity. m
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