As part of a staged rollout, a new email client was installed on some of the computers of a major company's customer service representatives (CSRS). One ofthe company's performance analysts has been tasked with estimating the difference on the busiest day of the year between the mean time (in minutes) spentworking on email for CSRS using the new email client and the mean time (in minutes) spent working on email for CSRS using the old email client.On the busiest day of the year, the performance analyst studies a random sample of 16 CSRS using the new email client and a random sample of 18 CSRS usingthe old email client. (These samples are chosen independently.) The analyst records the amount of time (in minutes) each CSR spends working on email. Thesedata are shown in the table.Times working on email (in minutes)New email client 166, 188, 207, 172, 202, 148, 192, 173, 197, 197, 158, 172, 209, 185, 203, 169Old email client 78, 196, 145, 195, 109, 85, 95, 138, 232, 47, 146, 122, 184, 247, 171, 132, 141, 142Send data to calculator VAssume that the two populations of times are approximately normally distributed. Let u, be the population mean time spent working on email by CSRS using thenew client. Let us be the population mean time spent working on email by CSRS using the old client.Construct a 99% confidence interval for the difference μ₁-₂. Then find the lower and upper limit of the 99% confidence interval. Carry your intermediatecomputations to three or more decimal places. Round your answers to two or more decimal places. (If necessary, consult a list of formulas.)WSLower limit:Upper limit:Continue8EDC144RFVX965TG3f6 CB6B17 33YH&7NUhp819TB1M(O915Kno13DNOaltmnoJ[www]S3P112BOSubmit AssignmentscrollCRE+ !!pausetamentbackspaenT shi

From the given information, x1 x2 166 78 188 196 207 145 172 195 202 109 148 85…

Answered: As part of a staged rollout, a new…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Why is the combination of the measures of central tendency and measures of variation so informative about a data set? Explain how they work together to provide a complete picture.
A researcher investigated four different word lists for use in hearing assessments. She wanted to know whether the lists were equally difficult to understand in the presence of a noisy background. To find out, she tested 96 subjects with normal hearing. She randomly assigned 24 to each of the four word lists and measured the number of words perceived correctly in the presence of background noise. Here are the summary statistics for number of words perceived correctly for each of the four words lists. Sample size Sample mean Sample standard deviation Word List A 24 32.5 5.1 Word List B 24 34.0 7.1 Word List C 24 25.75 6.3 Word List D 24 26.25 6.7 Suppose an F-test is to be performed. Which of the following is the correct null hypothesis?
Dr. V. noticed that the more frequently a student is late or absent from class the worse he or she performs on the final exam. He decided to investigate. Dr. V. collected a random sample of 22 students. This sample includes the number of times a student is absent and their grades on the final exam. The data can be found in the Excel file Assignment10.xlsx. Do not use any software that I did not assign. Times Late/ Final Exam Absent Grade 9 84.00 92.50 12 52.00 5 87.00 11 75.00 24 45.00 39.00 10 46.00 19 63.00 2 65.00 2 98.00 17 24.50 8 58.00 20 69.50 55 49.00 23 68.50 70.00 4 75.50 2 85.00 97.00 2 97.00 2 93.50 93.50 2 78.00 2 86.00 2 88.00 Question 1: Which or the two variables (times absent or grades on the final exam) is the independent variable and which is the dependent variable? Question 2: Using Microsoft Excel: (Excel file Assignment10.xlsx) SHOW YOUR WORK а. Count the number of XY variables. b. Calculate the mean and sample standard deviation of both the independent and…
An adventure company runs two obstacle courses, Fundash and Coolsprint. The designer of the courses suspects that the mean completion time of Fundash is not equal to the mean completion time of Coolsprint. To test this, she selects 205 Fundash runners and 300 Coolsprint runners. (Consider these as random samples of the Fundash and Coolspring runners.) The 205 Fundash runners complete the course with a mean time of 76.7 minutes and a standard deviation of 5.3 minutes. The 300 Coolsprint runners complete the course with a mean time of 77.5 minutes and a standard deviation of 5.1 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the mean completion time, ,, of Fundash is not equal to the mean completion time, μ₂, of Coolsprint? Perform a two-tailed test.…
A chess analyst is interested in whether the time that it takes to make a move is significantly different among chess players. He records the time in seconds for three chess players: Fabiano Caruana, Sergey Karjakin, and Wesley So during world chess candidates’ tournament 2018. You are given: Sum of Squares Within Groups (SSW) = 39021.57, Total Sum of Squares = 42152.88. Calculate the Mean Sum of Squares Between Groups.
An adventure company runs two obstacle courses, Fundash and Coolsprint. The designer of the courses suspects that the mean completion time of Fundash is not equal to the mean completion time of Coolsprint. To test this, she selects 250 Fundash runners and 285 Coolsprint runners. (Consider these as random samples of the Fundash and Coolspring runners.) The 250 Fundash runners complete the course with a mean time of 76.7 minutes and a standard deviation of 5.7 minutes. The 285 Coolsprint runners complete the course with a mean time of 77.5 minutes and a standard deviation of 5.6 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the mean completion time, u, of Fundash is not equal to the mean completion time, µa, of Coolsprint? Perform a two-tailed test.…
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true or false MSBetween represents the variability that is only affected by unsystematic factors.
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Which of these gives the best measure of central tendency for the given data?

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