As part of a staged rollout, a new email client was installed on some of the computers of a major company's customer service representatives (CSRS). One ofthe company's performance analysts has been tasked with estimating the difference on the busiest day of the year between the mean time (in minutes) spentworking on email for CSRS using the new email client and the mean time (in minutes) spent working on email for CSRS using the old email client.On the busiest day of the year, the performance analyst studies a random sample of 16 CSRS using the new email client and a random sample of 18 CSRS usingthe old email client. (These samples are chosen independently.) The analyst records the amount of time (in minutes) each CSR spends working on email. Thesedata are shown in the table.Times working on email (in minutes)New email client 166, 188, 207, 172, 202, 148, 192, 173, 197, 197, 158, 172, 209, 185, 203, 169Old email client 78, 196, 145, 195, 109, 85, 95, 138, 232, 47, 146, 122, 184, 247, 171, 132, 141, 142Send data to calculator VAssume that the two populations of times are approximately normally distributed. Let u, be the population mean time spent working on email by CSRS using thenew client. Let us be the population mean time spent working on email by CSRS using the old client.Construct a 99% confidence interval for the difference μ₁-₂. Then find the lower and upper limit of the 99% confidence interval. Carry your intermediatecomputations to three or more decimal places. Round your answers to two or more decimal places. (If necessary, consult a list of formulas.)WSLower limit:Upper limit:Continue8EDC144RFVX965TG3f6 CB6B17 33YH&7NUhp819TB1M(O915Kno13DNOaltmnoJ[www]S3P112BOSubmit AssignmentscrollCRE+ !!pausetamentbackspaenT shi

From the given information, x1 x2 166 78 188 196 207 145 172 195 202 109 148 85…

Answered: As part of a staged rollout, a new…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher investigated four different word lists for use in hearing assessments. She wanted to know whether the lists were equally difficult to understand in the presence of a noisy background. To find out, she tested 96 subjects with normal hearing. She randomly assigned 24 to each of the four word lists and measured the number of words perceived correctly in the presence of background noise. Here are the summary statistics for number of words perceived correctly for each of the four words lists. Sample size Sample mean Sample standard deviation Word List A 24 32.5 5.1 Word List B 24 34.0 7.1 Word List C 24 25.75 6.3 Word List D 24 26.25 6.7 Suppose an F-test is to be performed. Which of the following is the correct null hypothesis?
An adventure company runs two obstacle courses, Fundash and Coolsprint. The designer of the courses suspects that the mean completion time of Fundash is not equal to the mean completion time of Coolsprint. To test this, she selects 205 Fundash runners and 300 Coolsprint runners. (Consider these as random samples of the Fundash and Coolspring runners.) The 205 Fundash runners complete the course with a mean time of 76.7 minutes and a standard deviation of 5.3 minutes. The 300 Coolsprint runners complete the course with a mean time of 77.5 minutes and a standard deviation of 5.1 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the mean completion time, ,, of Fundash is not equal to the mean completion time, μ₂, of Coolsprint? Perform a two-tailed test.…
An adventure company runs two obstacle courses, Fundash and Coolsprint. The designer of the courses suspects that the mean completion time of Fundash is not equal to the mean completion time of Coolsprint. To test this, she selects 250 Fundash runners and 285 Coolsprint runners. (Consider these as random samples of the Fundash and Coolspring runners.) The 250 Fundash runners complete the course with a mean time of 76.7 minutes and a standard deviation of 5.7 minutes. The 285 Coolsprint runners complete the course with a mean time of 77.5 minutes and a standard deviation of 5.6 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the mean completion time, u, of Fundash is not equal to the mean completion time, µa, of Coolsprint? Perform a two-tailed test.…
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Each year, marketing and information firm J.D. Power and Associates surveys new car owners 90 days after they have purchased their cars. The data collected are used to rate auto brands (Toyota, Ford, and others) on initial quality and initial customer satisfaction. USA Today reported both the number of manufacturing defects per 100 vehicles and a satisfaction score for all 33 brands sold in the United States.+ A research group decides to compare the mean number of defects for 2 specific models of cars, A and B, made this year by taking random samples of 100 cars of each model. USE SALT (a) After collecting the data, the research group calculates a 95% confidence interval to estimate the difference in population means. In this case, what is the population? O the defects O all cars made this year all cars for models A and B that were produced this year O the 100 cars from each model (b) Suppose the calculated confidence interval is (100, 104) number of defects. What is the value of the…
what data do into spss to receive the answers?
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At a local food processing plant, it used to take an average of 90 minutes for new workers to learn a food processing job. Recently the company installed a new food processing machine. The supervisor at the company wants to find if the mean time taken by new workers to learn the food processing procedure on this new machine is different from 90 minutes. A sample of 20 workers showed that it took, on average, 85 minutes for them to learn the food processing procedure on the new machine. It is known that the learning times for all new workers are normally distributed with a population standard deviation of 7 minutes. Use a significance level of 0.01 to test the claim that the mean time is different from 90 minutes. What is the decision? A) Reject Ho because the test statistic is in the critical region and the p-value is greater than the significance level. B) Reject Ho because the test statistic is not in the critical region and the p-value is greater than the significance level.…

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