As part of å fündraišer, raffle tickets were sold to participants for a chance to win a gift card in one of the following amounts: $5, $10, $20, and $50. Among the 150 raffle tickets sold, 9 tickets wll be chosen that award $5 each, 6 tickets will be chosen that award $10 each, 4 tickets will be chosen that award $20 each, and 1 ticket will be chosen that awards $50. The tickets will be chosen randomly and without replacement, and each ticket is equally likely to be chosen. If a participant purchased one ticket, what is the probability of that participant winning a gift card of any amount? A 20 150 65 150 85 150 D 130 150
Permutations and Combinations
If there are 5 dishes, they can be relished in any order at a time. In permutation, it should be in a particular order. In combination, the order does not matter. Take 3 letters a, b, and c. The possible ways of pairing any two letters are ab, bc, ac, ba, cb and ca. It is in a particular order. So, this can be called the permutation of a, b, and c. But if the order does not matter then ab is the same as ba. Similarly, bc is the same as cb and ac is the same as ca. Here the list has ab, bc, and ac alone. This can be called the combination of a, b, and c.
Counting Theory
The fundamental counting principle is a rule that is used to count the total number of possible outcomes in a given situation.
![### Probability in Raffle Tickets
As part of a fundraiser, raffle tickets were sold to participants for a chance to win a gift card in one of the following amounts: $5, $10, $20, and $50. Among the 150 raffle tickets sold, 9 tickets will be chosen that award $5 each, 6 tickets will be chosen that award $10 each, 4 tickets will be chosen that award $20 each, and 1 ticket will be chosen that awards $50. The tickets will be chosen randomly and without replacement, and each ticket is equally likely to be chosen. If a participant purchased one ticket, what is the probability of that participant winning a gift card of any amount?
#### Options:
- **A.** \( \frac{20}{150} \)
- **B.** \( \frac{65}{150} \)
- **C.** \( \frac{85}{150} \)
- **D.** \( \frac{130}{150} \)
To find the correct answer, we need to determine the probability that a ticket will be selected for any prize.
- Total number of winning tickets = 9 (for $5) + 6 (for $10) + 4 (for $20) + 1 (for $50)
= 20 winning tickets
- Total number of tickets = 150
The probability of winning any prize is the number of winning tickets divided by the total number of tickets:
\[ \text{Probability} = \frac{20}{150} = \frac{2}{15} \]
Therefore, the correct option is:
- **A.** \( \frac{20}{150} \)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe220239e-d0de-4105-a4b5-1c7ec9906df9%2F93bcbeaf-f256-4da2-906f-fa44d46bb5ea%2Fhkysnk_processed.jpeg&w=3840&q=75)

Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 2 images




