As indicated in Fig. P8.52, a power plant similar to that in Fig. 8.11 operates on a regenerative vapor power cycle with one closed feedwater heater. Steam enters the first turbine stage at state 1 where pressure is 12 MPa and temperature is 560 C. Steam expands to state 2 where pressure is 1 MPa and some of the steam is extracted and diverted to the closed feedwater heater. Condensate exits the feedwater heater at state 7 as saturated liquid at a pressure of 1 MPa, undergoes a throttling process through a trap to a pressure of 6 kPa at state 8, and then enters the condenser. The remaining steam expands through the second turbine stage to a pressure of 6 kPa at state 3 and then enters the condenser. Saturated liquid feedwater exiting the condenser at state 4 at a pressure of 6 kPa enters a pump and exits the pump at a pressure of 12 MPa. The feedwater then flows through the closed feedwater heater, exiting at state 6 with a pressure of 12 MPa. The net power output for the cycle is 330 MW. For isentropic processes in each turbine stage and the pump, determine (a) the cycle thermal efficiency (%). Determine (b) the mass flow rate into the first turbine stage, in kg/s. Determine (c) the rate of entropy production in the closed feedwater heater, in kW/K.
As indicated in Fig. P8.52, a power plant similar to that in Fig. 8.11 operates on a regenerative vapor power cycle with one closed feedwater heater. Steam enters the first turbine stage at state 1 where pressure is 12 MPa and temperature is 560 C. Steam expands to state 2 where pressure is 1 MPa and some of the steam is extracted and diverted to the closed feedwater heater. Condensate exits the feedwater heater at state 7 as saturated liquid at a pressure of 1 MPa, undergoes a throttling process through a trap to a pressure of 6 kPa at state 8, and then enters the condenser. The remaining steam expands through the second turbine stage to a pressure of 6 kPa at state 3 and then enters the condenser. Saturated liquid feedwater exiting the condenser at state 4 at a pressure
of 6 kPa enters a pump and exits the pump at a pressure of 12 MPa. The feedwater then flows through the closed feedwater heater, exiting at state 6 with a pressure of 12 MPa. The net power output for the cycle is 330 MW.
For isentropic processes in each turbine stage and the pump, determine (a) the cycle thermal efficiency (%). Determine (b) the mass flow rate into the first turbine stage, in kg/s. Determine (c) the rate of entropy production in the closed feedwater heater, in kW/K.
![T
6
5
4
p= 12 MPa
7 p= 1 MPa
8
Steam
generator
p = 6 kPa
3
(v)
www
Closed
feedwater
heater
(1)
S
Condenser
7
IK~
Pump
State p (kPa) T (°C)
1
560
2
3
4
5
6
7
8
12,000
1,000
6
6
12,000
12,000
1,000
6
13³ ↓ (1-9)
Trap 8
(y)
Qout
T
h (kJ/kg) s (kJ/kg-K)
3506.2
6.6840
2823.3
6.6840
2058.2
6.6840 0.7892
151.53
0.5210
0
163.60
0.5210
606.61
1.7808
762.81
2.1387
762.81
2.4968
5
6
7
X
0
0.2530
Fig. 8.11 Regenerative vapor power cycle with one closed feedwater heater.
Fig. P8.52](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3a5c5b67-7e5e-4dfc-b43f-e0cf8554db93%2Fe0f12375-186f-4fa1-9799-8226fa140096%2Fm8t8lo_processed.jpeg&w=3840&q=75)
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