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As in the last problem, electrons are accelerated through a potential difference of 36.9 V and then shot through a thin slice of a crystal lattice, which acts like a double slit. A fluorescent screen 4.99 m behind the lattice lights up where the electron strikes, and you see a diffraction pattern. If the distance between the "slits" is 1.36 nm and the screen is large enough, how many maxima appear on the screen? As you did last time, give an integer answer. (If your answer is 124.999, give the answer as 124.)

As in the last problem, electrons are accelerated through a potential difference of 36.9 V and then shot through a thin slice of a crystal lattice, which acts like a double slit. A fluorescent screen 4.99 m behind the lattice lights up where the electron strikes, and you see a diffraction pattern. If the distance between the "slits" is 1.36 nm and the screen is large enough, how many maxima appear on the screen? As you did last time, give an integer answer. (If your answer is 124.999, give the answer as 124.)

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As in the last problem, electrons are accelerated through a potential difference of 36.9 V and then shot through a thin slice of a crystal lattice, which acts like a double slit. A fluorescent screen 4.99 m behind the lattice lights up where the electron strikes, and you see a diffraction pattern. 1.36 nm and the screen is large enough, how many maxima appear on the screen? If the distance between the "slits" is As you did last time, give an integer answer. (If your answer is 124.999, give the answer as 124.)
Transcribed Image Text:As in the last problem, electrons are accelerated through a potential difference of 36.9 V and then shot through a thin slice of a crystal lattice, which acts like a double slit. A fluorescent screen 4.99 m behind the lattice lights up where the electron strikes, and you see a diffraction pattern. 1.36 nm and the screen is large enough, how many maxima appear on the screen? If the distance between the "slits" is As you did last time, give an integer answer. (If your answer is 124.999, give the answer as 124.)
Suppose electrons are accelerated through a potential difference of 10.2 V and then shot through a thin slice of a crystal lattice, which acts like a double slit. A fluorescent screen 5.34 m behind the lattice lights up where the electron strikes, and you see a diffraction pattern. If the distance between the "slits" in the lattice is 47.5 nm: calculate the distance, in cm, between the central and first maxima on the fluorescent screen.
Transcribed Image Text:Suppose electrons are accelerated through a potential difference of 10.2 V and then shot through a thin slice of a crystal lattice, which acts like a double slit. A fluorescent screen 5.34 m behind the lattice lights up where the electron strikes, and you see a diffraction pattern. If the distance between the "slits" in the lattice is 47.5 nm: calculate the distance, in cm, between the central and first maxima on the fluorescent screen.
Expert Solution
Step 1

Given,

Double slit diffraction and pattern on the screen 

Step 2

(1) 

Here ,

wavelength of elctrons λ=1.227 nmVλ=1.227 nm36.9λ=0.202nmthen dsinθ=mλfor maxima sinθ=1m=d*1λm=1.36 nm0.202 nmm=6.73m=6

 

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