As in Example 1c of Section 5.1, assume tan e = -2.7, and e is in the second quadrant. Use one of the fundamental identities to find cot(-0). Provide 4 decimal places. Answer:

Trigonometry (11th Edition)
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ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
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Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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The second image is Example 1.c. For reference
As in Example 1c of Section 5.1, assume \(\tan \theta = -2.7\), and \(\theta\) is in the second quadrant. Use one of the fundamental identities to find \(\cot(-\theta)\). Provide 4 decimal places.

**Answer:**
Transcribed Image Text:As in Example 1c of Section 5.1, assume \(\tan \theta = -2.7\), and \(\theta\) is in the second quadrant. Use one of the fundamental identities to find \(\cot(-\theta)\). Provide 4 decimal places. **Answer:**
The image contains a trigonometry exercise involving the manipulation of trigonometric identities. Below is a transcription with explanations:

### Trigonometric Identities and Calculations

- **Given:**
  - \(\sin \theta = \frac{5 \sqrt{34}}{34}\)

- **Objective:**
  - Use reciprocal identities to relate the tangent and cotangent functions.

#### Example Problem

- **Expression:**
  \[
  \cot(-\theta)
  \]

- **Calculations:**
  1. **Reciprocal Identity:**
     \[
     \cot(-\theta) = \frac{1}{\tan(-\theta)}
     \]

  2. **Even-Odd Identity:**
     - \(\tan(-\theta) = -\tan(\theta)\)

  3. **Substitute and Simplify:**
     \[
     = \frac{1}{-\tan(\theta)} = -\frac{1}{\tan(\theta)}
     \]

  4. **Further Simplification:**
     \[
     = -\left(\frac{1}{\frac{5}{3}}\right) = -\left(\frac{3}{5}\right)
     \]

  5. **Multiply and Rewrite:**
     \[
     = 1 \div \left(\frac{5}{3}\right) = 1 \cdot \frac{3}{5} = \frac{3}{5}
     \]

#### Exercises

Now try solving these similar problems:

- **Exercises:**
  - 11
  - 19
  - 31

This section demonstrates the application of reciprocal identities and even-odd identities associated with trigonometric functions to solve expressions involving cotangents and tangents. It is important to thoroughly understand these identities to simplify and solve trigonometric problems effectively.
Transcribed Image Text:The image contains a trigonometry exercise involving the manipulation of trigonometric identities. Below is a transcription with explanations: ### Trigonometric Identities and Calculations - **Given:** - \(\sin \theta = \frac{5 \sqrt{34}}{34}\) - **Objective:** - Use reciprocal identities to relate the tangent and cotangent functions. #### Example Problem - **Expression:** \[ \cot(-\theta) \] - **Calculations:** 1. **Reciprocal Identity:** \[ \cot(-\theta) = \frac{1}{\tan(-\theta)} \] 2. **Even-Odd Identity:** - \(\tan(-\theta) = -\tan(\theta)\) 3. **Substitute and Simplify:** \[ = \frac{1}{-\tan(\theta)} = -\frac{1}{\tan(\theta)} \] 4. **Further Simplification:** \[ = -\left(\frac{1}{\frac{5}{3}}\right) = -\left(\frac{3}{5}\right) \] 5. **Multiply and Rewrite:** \[ = 1 \div \left(\frac{5}{3}\right) = 1 \cdot \frac{3}{5} = \frac{3}{5} \] #### Exercises Now try solving these similar problems: - **Exercises:** - 11 - 19 - 31 This section demonstrates the application of reciprocal identities and even-odd identities associated with trigonometric functions to solve expressions involving cotangents and tangents. It is important to thoroughly understand these identities to simplify and solve trigonometric problems effectively.
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