As an excited electron jumps from a higher energy level E, to a lower one E(n-1), the wavelength (A) of the emitted light would be Ohc/(En-E(n-1)) O hc/√(En-E(n-1)) Ohc²/(En-E(n-1) Ohc/(En-E(n-1)²
As an excited electron jumps from a higher energy level E, to a lower one E(n-1), the wavelength (A) of the emitted light would be Ohc/(En-E(n-1)) O hc/√(En-E(n-1)) Ohc²/(En-E(n-1) Ohc/(En-E(n-1)²
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![As an excited electron jumps from a higher energy level En to a lower one E(n-1), the wavelength
(X) of the emitted light would be
O hc/(En-E(n-1))
hc/√(En-E(n-1))
hc²/(En-E(n-1))
hc/(En-E(n-1))²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8c939cff-bc46-4066-b22a-d4e55e2c89ab%2F7ce64984-a4ee-4e45-b10b-559ab004a468%2Fs1v8nr3_processed.png&w=3840&q=75)
Transcribed Image Text:As an excited electron jumps from a higher energy level En to a lower one E(n-1), the wavelength
(X) of the emitted light would be
O hc/(En-E(n-1))
hc/√(En-E(n-1))
hc²/(En-E(n-1))
hc/(En-E(n-1))²
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