As a stone falls from the building, what is true about the vertical velocity as each second passes? O The vertical velocity cannot be determined. O The vertical velocity does not change. O It is -9.8 m/s at each second. O The vertical velocity increases by -9.8 m/s every second
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- Physics QuestionA motorcycle starts from rest with an initial acceleration of 3.3 m/s?, and the acceleration then changes with distance s as shown. dv Determine the velocity v of the motorcycle when s = 250 m. At this point also determine the value of the derivative - ds 6.6 4.4 2.2 125 250 8, m Answers: V = i m/s dv ds a, m/s²A roof worker loses his grip on his box of tools while working on a tall house. His box slides down the roof. The roof is angled at 29 degrees with the horizontal. The roof is made of a frictionless material. The box travels 5 m down the roof and then leaves the edge of it 12 m above the ground. a). Figure out the box's velocity as it leaves the house's roof? b). How far from the base of the house does the box hit the ground? c). By how much does the box clear the yard fence which is 1.8m tall and located 6.7m away from the base of the house? I TOOLS 5m 29° 12 m 1.8m 6-7m ENGL
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- -b+√b²-4ac 2a x = xo + vot + ½ât², v = vô + āt, v² = v² + 2ảAx, t = ² Problem 1: A ball is thrown straight up from the ground. The ball reaches a maximum height of 5 m. For simplicity, use g = 10 m/sec². a) What is the initial speed of the ball? Answer: 10 m/sec b) What is the time it takes the ball to reach the maximum height of 5 m? Answer: 1 sec c) What is the time it takes the ball to hit the ground? Answer: 2 sec d) At what times is the ball at a height of 3 m above the ground? Answer: 0.37 sec and 1.63 sec e) What is the velocity of the ball when it is at a height of 3 m above the ground? Answer: +6.3 m/sec or -6.3 m/sec.Note the expression: y = x. Which statement is most consistent with this expression? O if x triples, then y doubles O ifx doubles, then y doubles O ifx doubles, then y quadruples O ify doubles, then x quadruples O y is greater than xThe trajectory of an arrow traveling in Earth's gravity without air resistance is shown below at points a through e. The arrow has initial speed vo and is launched at angle to the horizontal. The vertical dashed lines represent equal time interval, At. (Note: = 9.81 m/s²) y(m) Vo a b At point c the horizontal velocity is: Vo sin (0) – ½ g (2At)2 Vo cos (0) Vo sin (0) + ½ g (24t)2 Vo cos (0) + ½ g (2At)2 e (1) x(m).