As a small illustration of Chinese remainder theorem that can all be solved mentally, say M = 30. Let’s say we express this M as the product of the pair wise co primes 2, 3, and 5. That is, m1 = 2, m2 = 3, and m3 = 5. Given that the numbers involved are small, calculate (75 + 89) mod 30, (75 × 89) mod 30, etc., using the Chinese Remainder Theorem. Verify your answers by direct computations on the operands in each case.
As a small illustration of Chinese remainder theorem that can all be solved mentally, say M = 30. Let’s say we express this M as the product of the pair wise co primes 2, 3, and 5. That is, m1 = 2, m2 = 3, and m3 = 5. Given that the numbers involved are small, calculate (75 + 89) mod 30, (75 × 89) mod 30, etc., using the Chinese Remainder Theorem. Verify your answers by direct computations on the operands in each case.
Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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As a small illustration of Chinese remainder theorem that can all be solved mentally, say M = 30. Let’s say we express this M as the product of the pair wise co primes 2, 3, and 5. That is, m1 = 2, m2 = 3, and m3 = 5. Given that the numbers involved are small, calculate (75 + 89) mod 30, (75 × 89) mod 30, etc., using the Chinese Remainder Theorem. Verify your answers by direct computations on the operands in each case.
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