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As a measure of productivity, a cell phone company records the number of customers each of its retail employees activates weekly. An activation is defined as either a new customer signing a cell phone contract or an existing customer renewing a contract. The accompanying table shows the number of weekly activations for eight randomly selected employees along with their job-satisfaction levels rated on a scale of 1-10 (10 = Most satisfied). Complete parts a through d. E Click the icon to view the table showing activations and satisfaction. The coefficient of determination is 0.674. (Type an integer or decimal rounded to three decimal places as needed.) b. Using a = 0.05, test the significance of the population coefficient of determination. The hypotheses for this test are Ho: p? = 0 and H,: p? > 0. The test statistic is 12.38 (Type an integer or decimal rounded to two decimal places as needed.) The p-value is 0.013 (Type an integer or decimal rounded to three decimal places as needed.) Therefore, at the 0.05 level of significance, reject the null hypothesis. There is sufficient evidence to conclude that the coefficient of determination is greater than zero. c. Construct a 95% confidence interval for the average number of activations made by an employee with a job-satisfaction score of 8.2. The confidence interval is ( ) (Type integers or decimals rounded to one decimal place as needed.)

As a measure of productivity, a cell phone company records the number of customers each of its retail employees activates weekly. An activation is defined as either a new customer signing a cell phone contract or an existing customer renewing a contract. The accompanying table shows the number of weekly activations for eight randomly selected employees along with their job-satisfaction levels rated on a scale of 1-10 (10 = Most satisfied). Complete parts a through d. E Click the icon to view the table showing activations and satisfaction. The coefficient of determination is 0.674. (Type an integer or decimal rounded to three decimal places as needed.) b. Using a = 0.05, test the significance of the population coefficient of determination. The hypotheses for this test are Ho: p? = 0 and H,: p? > 0. The test statistic is 12.38 (Type an integer or decimal rounded to two decimal places as needed.) The p-value is 0.013 (Type an integer or decimal rounded to three decimal places as needed.) Therefore, at the 0.05 level of significance, reject the null hypothesis. There is sufficient evidence to conclude that the coefficient of determination is greater than zero. c. Construct a 95% confidence interval for the average number of activations made by an employee with a job-satisfaction score of 8.2. The confidence interval is ( ) (Type integers or decimals rounded to one decimal place as needed.)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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ers each of its retail employees activates we of activations and satisfactic Activations Satisfaction O 37 8.0 22 7.9 37 8.5 37 9.0 18 6.1 27 7.0 32 8.2 28 77 Print Done ade by an employee with a job-satisfaction score of Doorson
Transcribed Image Text:ers each of its retail employees activates we of activations and satisfactic Activations Satisfaction O 37 8.0 22 7.9 37 8.5 37 9.0 18 6.1 27 7.0 32 8.2 28 77 Print Done ade by an employee with a job-satisfaction score of Doorson
As a measure of productivity, a cell phone company records the number of customers each of its retail employees activates weekly. An activation is defined as either a new customer signing a cell phone contract or an existing customer renewing a contract. The accompanying table shows the number of weekly activations for eight randomly selected employees along with their job-satisfaction levels rated on a scale of 1-10 (10 = Most satisfied). Complete parts a through d. E Click the icon to view the table showing activations and satisfaction. The coefficient of determination is 0.674 (Type an integer or decimal rounded to three decimal places as needed.) b. Using a = 0.05, test the significance of the population coefficient of determination. The hypotheses for this test are Ho: p² = 0 and H,: p? > 0. The test statistic is 12.38 (Type an integer or decimal rounded to two decimal places as needed.) The p-value is 0.013. (Type an integer or decimal rounded to three decimal places as needed.) Therefore, at the 0.05 level of significance, reject the null hypothesis. There is sufficient evidence to conclude that the coefficient of determination is greater than zero. c. Construct a 95% confidence interval for the average number of activations made by an employee with a job-satisfaction score of 8.2. The confidence interval is (). (Type integers or decimals rounded to one decimal place as needed.)
Transcribed Image Text:As a measure of productivity, a cell phone company records the number of customers each of its retail employees activates weekly. An activation is defined as either a new customer signing a cell phone contract or an existing customer renewing a contract. The accompanying table shows the number of weekly activations for eight randomly selected employees along with their job-satisfaction levels rated on a scale of 1-10 (10 = Most satisfied). Complete parts a through d. E Click the icon to view the table showing activations and satisfaction. The coefficient of determination is 0.674 (Type an integer or decimal rounded to three decimal places as needed.) b. Using a = 0.05, test the significance of the population coefficient of determination. The hypotheses for this test are Ho: p² = 0 and H,: p? > 0. The test statistic is 12.38 (Type an integer or decimal rounded to two decimal places as needed.) The p-value is 0.013. (Type an integer or decimal rounded to three decimal places as needed.) Therefore, at the 0.05 level of significance, reject the null hypothesis. There is sufficient evidence to conclude that the coefficient of determination is greater than zero. c. Construct a 95% confidence interval for the average number of activations made by an employee with a job-satisfaction score of 8.2. The confidence interval is (). (Type integers or decimals rounded to one decimal place as needed.)
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