as 2 (2.) (a.) Compute ro x re for the parameterization of the sphere of radius a in terms of the spherical variables and . This result may be used on the problem on the following page if you like. done in class / book +oxro = < a ²sin² (p) aus (e), a² sin² (0) Six (0), I²Sin (4) con(d)) (b.) Evaluate r× r₁ at 0 = 0, 0 = 1. Use this to determine whether the normal would be outwards or inwards oriented. (to xre)(0, 1) = {a² - 1.1, a².1.0, a².1.07 = : Since (0,5/2)→ * outwards. (c.) Evaluate rø × rẻ at 0 = 0, ¢ = 0. Does this make sense? Explain what's going on here, since our surface is well behaved. (you are free to use the internet to research this). raxro(0,0) = 40,0,07 ! orienter the surface ✓ is well behavied meaning n to ň ₤o !! an artificial singularity and this is called. old choice of parameterization as it is at of the domain in 2/4 space G the ОСШ For and points

Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Please review and solve the following problem. The screenshot listed already has some work done and the correct answer listed. Please solve the problem and include an explanation of how the work was solved. Also, Please make sure to double check the answer provided matches up with the screenshot and the work is properly formatted so I am able to follow along. Thanks :)

as
2
(2.) (a.) Compute ro x re for the parameterization of the sphere of radius a in terms of the spherical
variables and . This result may be used on the problem on the following page if you like.
done in class / book
+oxro = < a ²sin² (p) aus (e), a² sin² (0) Six (0), I²Sin (4) con(d))
(b.) Evaluate r× r₁ at 0 = 0, 0 = 1. Use this to determine whether the normal would be outwards or
inwards oriented.
(to xre)(0, 1) = {a² - 1.1, a².1.0,
a².1.07
=
: <a², 0, 0>
Since
(0,5/2)→
*
outwards.
(c.) Evaluate rø × rẻ at 0 = 0, ¢ = 0. Does this make sense? Explain what's going on here, since our
surface is well behaved. (you are free to use the internet to research this).
raxro(0,0) = 40,0,07 !
orienter
the surface
✓
is
well behavied
meaning n to
ň ₤o !!
an artificial singularity and
this is called.
old choice
of parameterization
as
it is at
of
the domain in
2/4 space
G
the
ОСШ
For
and points
Transcribed Image Text:as 2 (2.) (a.) Compute ro x re for the parameterization of the sphere of radius a in terms of the spherical variables and . This result may be used on the problem on the following page if you like. done in class / book +oxro = < a ²sin² (p) aus (e), a² sin² (0) Six (0), I²Sin (4) con(d)) (b.) Evaluate r× r₁ at 0 = 0, 0 = 1. Use this to determine whether the normal would be outwards or inwards oriented. (to xre)(0, 1) = {a² - 1.1, a².1.0, a².1.07 = : <a², 0, 0> Since (0,5/2)→ * outwards. (c.) Evaluate rø × rẻ at 0 = 0, ¢ = 0. Does this make sense? Explain what's going on here, since our surface is well behaved. (you are free to use the internet to research this). raxro(0,0) = 40,0,07 ! orienter the surface ✓ is well behavied meaning n to ň ₤o !! an artificial singularity and this is called. old choice of parameterization as it is at of the domain in 2/4 space G the ОСШ For and points
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