arrent.cap ournal Help tup pt 1 Procedure 1: Force vs Current Procedure 2: Force vs Length Conclusions Force vs Current for Constant Length Procedure 1: Force vs Current for Constant Length Run #1 Set 1. With conductor 42 inserted into the current balance record the value on the scale (in grams) for zero current in the table. Force for Current (gm) Current (A) 1 167.0 0.0 2. Increase the current to 0.5 A and again record the value on the scale in the table. 167.3 0.5 3 167.6 1.0 168.0 1.5 3. Continue increasing the current by 0.5 A and recording the values on the scale until you reach 5.0 A. TURN THE CURRENT OFF. 5. 168.3 2.0 6. 168.6 2.5 7. 168.9 3.0 4. Record the slope of the graph and along with the length of conductor 42 determine the magnetic field. 8. 169.3 3.5 169.6 4.0 10 169.9 4.5 11 170.3 5.0 Conductor Length = 8.4 cm 1.670 F forl Slope =_0.00644 TA %3D Run #1 1.665 1.660 Magnetic Field = 1.655 1.650 1.645 Linear mx + b m = 0.00644 + 5.9x10- 1.640 b = 1.64 + 1.7x104 1.635 0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 Current (A) Force vs Current for Constant Length 00:00.00 Common Rate --Hz (N)IJOJ
arrent.cap ournal Help tup pt 1 Procedure 1: Force vs Current Procedure 2: Force vs Length Conclusions Force vs Current for Constant Length Procedure 1: Force vs Current for Constant Length Run #1 Set 1. With conductor 42 inserted into the current balance record the value on the scale (in grams) for zero current in the table. Force for Current (gm) Current (A) 1 167.0 0.0 2. Increase the current to 0.5 A and again record the value on the scale in the table. 167.3 0.5 3 167.6 1.0 168.0 1.5 3. Continue increasing the current by 0.5 A and recording the values on the scale until you reach 5.0 A. TURN THE CURRENT OFF. 5. 168.3 2.0 6. 168.6 2.5 7. 168.9 3.0 4. Record the slope of the graph and along with the length of conductor 42 determine the magnetic field. 8. 169.3 3.5 169.6 4.0 10 169.9 4.5 11 170.3 5.0 Conductor Length = 8.4 cm 1.670 F forl Slope =_0.00644 TA %3D Run #1 1.665 1.660 Magnetic Field = 1.655 1.650 1.645 Linear mx + b m = 0.00644 + 5.9x10- 1.640 b = 1.64 + 1.7x104 1.635 0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 Current (A) Force vs Current for Constant Length 00:00.00 Common Rate --Hz (N)IJOJ
Related questions
Question
Determine the slope and the magnetic field
Transcribed Image Text:urrent.cap*
Mournal Help
tup pt 1
Procedure 1: Force vs Current Procedure 2: Force vs Length
Conclusions
Procedure 1: Force vs Current for Constant Length
Force vs Current for Constant Length
A Run #1
Set
1. With conductor 42 inserted into the current
balance record the value on the scale (in grams) for
zero current in the table.
Force for Current
Current
(gm)
(A)
1
167.0
0.0
2. Increase the current to 0.5 A and again record
the value on the scale in the table.
2
167.3
0.5
167.6
1.0
4
168.0
1.5
3. Continue increasing the current by 0.5 A and
recording the values on the scale until you reach
5.0 A. TURN THE CURRENT OFF.
168.3
2.0
6
168.6
2.5
7
168.9
3.0
4. Record the slope of the graph and along with the
length of conductor 42 determine the magnetic
field.
8
169.3
3.5
9
169.6
4.0
10
169.9
4.5
11
170.3
5.0
Conductor Length = 8.4 cm
1.670
F forl
Slope =_0.00644_
TA
Run #1
1.665
1.660
Magnetic Field =
T
1.655
1.650
1.645
Linear
mx + b
1.640
m = 0.00644 + 5.9x10-
+ 1.7x104
b = 1.64
1.635
0.0
0.5
1.0
1.5
2.0
2.5
3.0
3.5
4.0
4.5
5.0
Current (A)
Force vs Current for Constant Length
00:00.00
Common Rate
--Hz
Recording
stinuous Modo
Delete Last Run
(N)IJ0
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 5 steps
