Arrange the steps in the correct order to prove that if x is a real number and m is an integer, then a+m| = |x|+m. Rank the options below. Suppose that [z] =n, where n is an integer. Using the property [2] = n if and only if n-1 < x≤ n again, we see that [x+m] =n+m= [x] + m. By using the property [2] = n if and only if n-1
Arrange the steps in the correct order to prove that if x is a real number and m is an integer, then a+m| = |x|+m. Rank the options below. Suppose that [z] =n, where n is an integer. Using the property [2] = n if and only if n-1 < x≤ n again, we see that [x+m] =n+m= [x] + m. By using the property [2] = n if and only if n-1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Arrange the steps in the correct order to prove that if x is a real number and m is an integer, then [x+m] = [x] + m.
Rank the options below.
Suppose that [x] = n, where n is an integer.
Using the property [] =n if and only if n-1 < x≤n again, we see that [+m] =n+m= [x] + m.
By using the property [2] = n if and only if n-1 < x≤ n, it follows that n-1 < x≤n.
Adding m to all three quantities in this chain of two inequalities shows that m+ n-15x+m<m+n.
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Transcribed Image Text:Arrange the steps in the correct order to prove that if x is a real number and m is an integer, then [x+m] = [x] + m.
Rank the options below.
Suppose that [x] = n, where n is an integer.
Using the property [] =n if and only if n-1 < x≤n again, we see that [+m] =n+m= [x] + m.
By using the property [2] = n if and only if n-1 < x≤ n, it follows that n-1 < x≤n.
Adding m to all three quantities in this chain of two inequalities shows that m+ n-15x+m<m+n.
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