Aristapedia is a lethal allele that is also dominant. Individuals with this trait must be heterozygous (Aa) because the homozygous condition (AA) is lethal. This is not a sex-linked trait. Wild-type flies do not carry the allele for aristopedia (aa). 4. Predict what the outcome of a cross between a wild-type fly and one with aristopedia. 5. Perform the cross and determine if your prediction is correct using statistical analysis. Summarize your results and Índicate whether your prediction is confirmed.

Human Anatomy & Physiology (11th Edition)
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Author:Elaine N. Marieb, Katja N. Hoehn
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please answer item no.4, 5, and 6 pleaseee.
Flies to be Mated
Female: +
Source: Design View
Male: AR
Source: Design View
Mate Elies
Remove Fly
Remoye Fly
Parents of Cross #1
Select Cross
Female: + N= 1
Male: AR; N = 1
a Select to Mate
Q Select to Mate
Offspring of Cross #1
Eemale: +; N = 226
Male: +N = 263
Eemale: AR; N = 250
Male AB: N = 268
Q Select to Mate
youn
a Select to Mate
Q Select to Mate
Q Select to Mate
Design
Mate
Crosses
Analyze Lab Notes
Copyright © 2019, Robert A. Desharnais, Ph.D.
Virtual Courseware Project, ScienceCourseware.org
Select Cross
O Ignore sex of flies
| Include a test of hypothesis
Results for Cross #1
Phenotype
Observed Proportion Hypothesis Probability
(0-E)?/E
Expected
Female: +
226
0.2244
251
0.2493
251.00
2.49
Male: +
Eemale:. AR
Male: AR
Total
263
0.2612
253
0.2512
253.00
0.40
250
0.2483
252
0.2502
252.00
0.02
268
0.2661
251
0.2493
251.00
1.15
1007
1.0000
1007
1.0000
1007.00
4.05
New Hypothesis
Chi-squared test statistic: 4.05
Degrees of freedom: 3
Level of significance: 0.2558
Add Results to Lab Notes
Transcribed Image Text:Flies to be Mated Female: + Source: Design View Male: AR Source: Design View Mate Elies Remove Fly Remoye Fly Parents of Cross #1 Select Cross Female: + N= 1 Male: AR; N = 1 a Select to Mate Q Select to Mate Offspring of Cross #1 Eemale: +; N = 226 Male: +N = 263 Eemale: AR; N = 250 Male AB: N = 268 Q Select to Mate youn a Select to Mate Q Select to Mate Q Select to Mate Design Mate Crosses Analyze Lab Notes Copyright © 2019, Robert A. Desharnais, Ph.D. Virtual Courseware Project, ScienceCourseware.org Select Cross O Ignore sex of flies | Include a test of hypothesis Results for Cross #1 Phenotype Observed Proportion Hypothesis Probability (0-E)?/E Expected Female: + 226 0.2244 251 0.2493 251.00 2.49 Male: + Eemale:. AR Male: AR Total 263 0.2612 253 0.2512 253.00 0.40 250 0.2483 252 0.2502 252.00 0.02 268 0.2661 251 0.2493 251.00 1.15 1007 1.0000 1007 1.0000 1007.00 4.05 New Hypothesis Chi-squared test statistic: 4.05 Degrees of freedom: 3 Level of significance: 0.2558 Add Results to Lab Notes
Aristapedia is a lethal allele that is
also dominant. Individuals with this
trait must be heterozygous (Aa)
because the homozygous condition
(AA) is lethal. This is not a sex-linked
trait. Wild-type flies do not carry the
allele for aristopedia (aa).
4. Predict what the
outcome of a cross
between a wild-type
fly and one with
aristopedia.
5. Perform the cross
and determine if your
prediction is correct
using statistical
analysis. Summarize
your results and
indicate whether your
prediction is
confirmed.
6. Suggest a reason
why a typical punnett
square prediction for
a heterozygous cross
might be accurate in
this case.
Transcribed Image Text:Aristapedia is a lethal allele that is also dominant. Individuals with this trait must be heterozygous (Aa) because the homozygous condition (AA) is lethal. This is not a sex-linked trait. Wild-type flies do not carry the allele for aristopedia (aa). 4. Predict what the outcome of a cross between a wild-type fly and one with aristopedia. 5. Perform the cross and determine if your prediction is correct using statistical analysis. Summarize your results and indicate whether your prediction is confirmed. 6. Suggest a reason why a typical punnett square prediction for a heterozygous cross might be accurate in this case.
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