area of this leaf ( the shaded part) by performing a definite integral. r = √ cos(30) f
area of this leaf ( the shaded part) by performing a definite integral. r = √ cos(30) f
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:First find the interval of 0 on which the given polar curve traces the loop in the 2nd quadrant (the loop that encloses the shaded leaf). Then, find the
area of this leaf (the shaded part) by performing a definite integral.
r = V cos (38)
4
-0.5
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