area of the region that lies to the right of the y-axis and to the left of the parabola x = 8y – y2 (the shaded region in the figure) is given by the integral (8y - y2) dv. (Turn your head clockwise and of the region as lying below the curve x - 8y - y² from y = 0 to y = 8.) Find the area of the region.
area of the region that lies to the right of the y-axis and to the left of the parabola x = 8y – y2 (the shaded region in the figure) is given by the integral (8y - y2) dv. (Turn your head clockwise and of the region as lying below the curve x - 8y - y² from y = 0 to y = 8.) Find the area of the region.
area of the region that lies to the right of the y-axis and to the left of the parabola x = 8y – y2 (the shaded region in the figure) is given by the integral (8y - y2) dv. (Turn your head clockwise and of the region as lying below the curve x - 8y - y² from y = 0 to y = 8.) Find the area of the region.
The area of the region that lies to the right of the y-axis and to the left of the parabola x = 8y − y2
(the shaded region in the figure) is given by the integral
8
∫
(8y − y2) dy
0
(Turn your head clockwise and think of the region as lying below the curve x = 8y − y2 from y = 0 to y = 8.) Find the area of the region.
Transcribed Image Text:The area of the region that lies to the right of the y-axis and to the left of the parabola x = 8y – y2 (the shaded region in the figure) is given by the integral
I (8y – y?) dy. (Turn your head clockwise and
think of the region as lying below the curve x = 8y – y2 from y = 0 to y = 8.) Find the area of the region.
y
x = 8 y - y
16
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
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